从mysql数据库解码json并将其显​​示在表php上

Question

我编码了一些存储在mysql数据库中的值。我想解码它们以使用PHP在桌面上显示。

我正在使用的示例查询：

$sql = "SELECT `coc_id`, `cc_id`, `category_options`FROM 
`ag_category_option_combos` WHERE coc_id='831'";
$result = $con->query($sql);

while ($row = $result->fetch_assoc()) {
# code...
// $data = array();
$data = json_decode($row['category_options'], true);

echo '  <tr>
            <td>' . $row['coc_id'] . '</td>
            <td>' . $row['cc_id'] . '</td>
            <td>' . $data['id'] .'</td>
            <td>' . $data['name'] .'</td>
        </tr>';

print_r($data);
echo $data;
}

示例数据库中的mysql数据：

  ----+---------------------+------------+                                                                                
  | coc_id | cc_id | category_options  | created_at          | updated_at |                                                                                
   +--------+-------+----------------------------------------------------------------------------------------------------------+---------------------+------------+                                                                                
  |     16 |    15 | {"categoryOption":{"id":"13","name":"default"}} | 2018-03-19 09:42:06 |            |                                                                                
  |    825 |   824 | {"categoryOption":[{"id":"798","name":"<15"},
  {"id":"821","name":"Male"}]}  | 2018-03-19 09:42:06 |            |                                                                                
  |    826 |   824 | {"categoryOption":[{"id":"798","name":"<15"},{"id":"822","name":"Female"}]}       | 2018-03-19 09:42:06 |            |                                                                                
  |    827 |   824 | {"categoryOption":[{"id":"799","name":"15 - 24"},{"id":"821","name":"Male"}]}            | 2018-03-19 09:42:06 |            |                                                                                
  |    828 |   824 | {"categoryOption":[{"id":"799","name":"15 - 24"},{"id":"822","name":"Female"}]}           | 2018-03-19 09:42:06 |            |                                                                                
  |    829 |   824 | {"categoryOption":[{"id":"800","name":"25 - 34"},{"id":"821","name":"Male"}]}           | 2018-03-19 09:42:06 |            |                                                                                
  |    830 |   824 | {"categoryOption":[{"id":"800","name":"25 - 34"},{"id":"822","name":"Female"}]}                          | 2018-03-19 09:42:06 |            |                                               

我现在想要的是每行显示coc_id和cc_id列上的所有项目，但是category_options中的一个值数组和下一行中的另一个数组

示例：使用上面示例mysql数据中的第2行

 <tr>
   <td>825</td>
   <td>824</td>
   <td>798</td>
   <td><15</td>
 </tr>

   <tr>
     <td>825</td>
     <td>824</td>
     <td>821</td>
     <td>Male</td>
   </tr>

我如何做到这一点？ 或者，如果有更好的方法，请提供建议

Answer 1

您可以遍历JSON中的所有元素，重复<tr>标记：

$data = json_decode($row['category_options'], true);

// Fix if $data['categoryOption'] is not an "array" of elements
if (isset($data['categoryOption']['id'])) {
    $data['categoryOption'] = [$data['categoryOption']];
}

// loop over $data['categoryOption'] array of the JSON:
foreach ($data['categoryOption'] as $item) {
    echo '<tr>
        <td>' . $row['coc_id'] . '</td>
        <td>' . $row['cc_id'] . '</td>
        <td>' . $item['id'] . '</td>
        <td>' . $item['name'] .'</td>
    </tr>';
}