Question

我想捕获子窗口的鼠标事件，但问题是鼠标事件没有传递给这个子窗口.... 在互联网上查找信息后，我发现我需要自定义按钮。但是在执行此操作后我仍然没有得到任何响应。谁能告诉我还需要做些什么来捕获这个子窗口中的鼠标事件？这是我的代码：

from PyQt5 import QtCore,QtWidgets
from PyQt5.QtWidgets import *
import sys

class My_top_Dialog(object):
    def setupUi(self, Dialog):
        Dialog.setObjectName("Dialog")
        Dialog.resize(640, 532)
        self.verticalLayout = QtWidgets.QVBoxLayout(Dialog)
        self.verticalLayout.setObjectName("verticalLayout")
        self.Products = MyButton()
        self.verticalLayout.addWidget(self.Products)
        self.Products.clicked.connect(self.accept)
        _translate = QtCore.QCoreApplication.translate
        Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
        self.Products.setText(_translate("Dialog", "top window"))

    def accept(self):
        self.dialog = QDialog()
        ui = My_second_Dialog()
        ui.setupUi(self.dialog)
        self.dialog.show()

class My_second_Dialog(object):
    def setupUi(self, Dialog):
        Dialog.setObjectName("Dialog")
        Dialog.resize(640, 480)
        self.verticalLayout = QtWidgets.QVBoxLayout(Dialog)
        self.verticalLayout.setObjectName("verticalLayout")
        self.fetch = MyButton()
        self.verticalLayout.addWidget(self.fetch)
        self.fetch.clicked.connect(self.accept)
        _translate = QtCore.QCoreApplication.translate
        Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
        self.fetch.setText(_translate("Dialog", "second window"))

    def accept(self):
        QMessageBox.information(self, "success",
                                "success.")
class MyButton(QPushButton):
    def __init__(self, parent=None):
        super(MyButton, self).__init__(parent)
        self.setFixedSize(111, 111)

    def mousePressEvent(self, QMouseEvent):
        if QMouseEvent.button() == QtCore.Qt.LeftButton:
            self.clicked.emit(True)
            self.parent().mousePressEvent(QMouseEvent)

if __name__ == '__main__':
    app = QApplication(sys.argv)
    dialog = QDialog()
    ui = My_top_Dialog()
    ui.setupUi(dialog)
    dialog.show()
    sys.exit(app.exec_())

Answer 1

这是解决问题的第二种方式。因为回复评论不能显示代码块，所以我在这里显示我的代码，我认为我的问题的根本原因是我没有完全关联主窗口和子窗口。是否它正在构建一个关系成员或直接继承一个类，这两个都可以使子窗口信号和触发器不受影响，这是我的代码：

from PyQt5 import QtCore,QtWidgets
from PyQt5.QtWidgets import *
import sys

class My_top_Dialog(object):
    def setupUi(self, Dialog):
        Dialog.setObjectName("Dialog")
        Dialog.resize(640, 532)
        self.verticalLayout = QtWidgets.QVBoxLayout(Dialog)
        self.verticalLayout.setObjectName("verticalLayout")
        self.Products = MyButton()
        self.verticalLayout.addWidget(self.Products)
        self.Products.clicked.connect(self.accept)
        _translate = QtCore.QCoreApplication.translate
        Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
        self.Products.setText(_translate("Dialog", "top window"))

    def accept(self):
        dialog = My_second_Dialog()
        dialog.exec_()

class My_second_Dialog(QDialog,My_top_Dialog):
    def __init__(self,parent = None):
        QDialog.__init__(self,parent)
        self.setupUi(self)
    def setupUi(self, Dialog):
        Dialog.setObjectName("Dialog")
        Dialog.resize(640, 480)
        self.verticalLayout = QtWidgets.QVBoxLayout(Dialog)
        self.verticalLayout.setObjectName("verticalLayout")
        self.fetch = MyButton()
        self.verticalLayout.addWidget(self.fetch)
        self.fetch.clicked.connect(self.accept)
        _translate = QtCore.QCoreApplication.translate
        Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
        self.fetch.setText(_translate("Dialog", "second window"))

    def accept(self):
        QMessageBox.information(self, "success",
                                "success.")
class MyButton(QPushButton):
    def __init__(self, parent=None):
        super(MyButton, self).__init__(parent)
        self.setFixedSize(111, 111)

    def mousePressEvent(self, QMouseEvent):
        if QMouseEvent.button() == QtCore.Qt.LeftButton:
            self.clicked.emit(True)
            self.parent().mousePressEvent(QMouseEvent)


if __name__ == '__main__':
    app = QApplication(sys.argv)
    dialog = QDialog()
    ui = My_top_Dialog()
    ui.setupUi(dialog)
    dialog.show()
    sys.exit(app.exec_())

Answer 2

试一试：

from PyQt5 import QtCore,QtWidgets
from PyQt5.QtWidgets import *
import sys

class My_top_Dialog(object):
    def setupUi(self, Dialog):
        Dialog.setObjectName("Dialog")
        Dialog.resize(640, 532)
        self.verticalLayout = QtWidgets.QVBoxLayout(Dialog)
        self.verticalLayout.setObjectName("verticalLayout")
        self.Products = MyButton()
        self.verticalLayout.addWidget(self.Products)
        self.Products.clicked.connect(self.accept)
        _translate = QtCore.QCoreApplication.translate
        Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
        self.Products.setText(_translate("Dialog", "top window"))

    def accept(self):
        self.dialog = QDialog()
        self.ui     = My_second_Dialog()
        self.ui.setupUi(self.dialog)
        self.dialog.show()

class My_second_Dialog(object):
    def setupUi(self, Dialog):
        Dialog.setObjectName("Dialog")
        Dialog.resize(640, 480)
        self.verticalLayout = QtWidgets.QVBoxLayout(Dialog)
        self.verticalLayout.setObjectName("verticalLayout")
        self.fetch = MyButton()
        self.verticalLayout.addWidget(self.fetch)
        self.fetch.clicked.connect(self.accept)
        _translate = QtCore.QCoreApplication.translate
        Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
        self.fetch.setText(_translate("Dialog", "second window"))

    def accept(self):
        QMessageBox.information(self.fetch, "Success", "success.")   # +++ self.fetch


class MyButton(QPushButton):
    def __init__(self, parent=None):
        super(MyButton, self).__init__(parent)
        self.setFixedSize(111, 111)

    def mousePressEvent(self, event): #QMouseEvent):
        if event.button() == QtCore.Qt.LeftButton:
            self.clicked.emit(True)
            #self.parent().mousePressEvent(QMouseEvent)               # --- 

if __name__ == '__main__':
    app = QApplication(sys.argv)
    dialog = QDialog()
    ui = My_top_Dialog()
    ui.setupUi(dialog)
    dialog.show()
    sys.exit(app.exec_())

子窗口无法在PyQt5中触发鼠标事件

2 个答案: