Question

你好，有代码

$bot.on("presenceUpdate", (oldMember, newMember) => {
  if(oldMember.presence.status !== newMember.presence.status){
    const memberID = newMember.user.id;
    if(newMember.user.presence.status === "online"){      
      membersOnline.push(memberID);
      console.log("-------online--------");
      console.log(membersOnline);
    }else
    if(newMember.user.presence.status === "offline"){
      membersOnline.filter(e => e !== memberID)
      console.log("-------offline--------");
      console.log(membersOnline);
    }
      console.log(`${newMember.user.username} is now ${newMember.presence.status}`);

  }
});

Resoults是id不被删除。

-------离线-------- []

-l - RACE - l-现在离线

-------在线-------- [＆＃39; 203287818330570752＆＃39; ]

-l - RACE - l-现在在线

-------离线-------- [＆＃39; 203287818330570752＆＃39; ]

-l - RACE - l-现在离线

-------在线-------- [＆＃39; 203287818330570752＆＃39;，＆＃39; 203287818330570752＆＃39; ]

-l - RACE - l-现在在线

DOCS

Answer 1

filter（）方法创建一个包含所有传递元素的新数组由提供的功能实现的测试。 https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

方法Array.prototype.filter（）不会更改原始数组。如此简单的解决方案是：

membersOnline = membersOnline.filter(e => e !== memberID);

Answer 2

我相信filter方法返回一个数组，因此在代码中运行方法但不将返回值赋给变量。请参阅下面的代码......

$bot.on("presenceUpdate", (oldMember, newMember) => {
    if(oldMember.presence.status !== newMember.presence.status){
      const memberID = newMember.user.id;
    }
    if(newMember.user.presence.status === "online"){      
        membersOnline.push(memberID);
        console.log("-------online--------");
        console.log(membersOnline);
    } else {
        if(newMember.user.presence.status === "offline"){
            var newOnlineMembers = membersOnline.filter(e => e !== memberID);  // add new variable for filtered array
            console.log("-------offline--------");
            console.log(newOnlineMembers); // output new variable
        }
        console.log(`${newMember.user.username} is now ${newMember.presence.status}`);
    }
});

JS - Discord Bot从数组中删除特定ID

2 个答案: