打字稿:如何在React中添加历史对象的类型检查?

时间:2018-03-17 22:12:37

标签: reactjs typescript typescript-typings

我有以下代码,它接收历史对象作为prop:

const ChildComponent = ({ history }) => (
        <div className={styles.body}>
            <div className={styles.cta}>
                <FloatingActionButton onClick={() => history.push(routes[4].path)}>
                    <span>Click me</span>
                </FloatingActionButton>
            </div>
        </div>
);

如何为此历史道具添加类型检查,通过使用withRouter HOC 包装它的父级来获得?我能想到的一种方法是写下这样的东西:

interface Props {
    history: {
        push(url: string): void;
    };
}

但我确定这不是正确的方法,因为历史对象的其他属性正在丢失。

你能建议正确的方法吗?

根据@ Oblosys的回答更新代码

import { withRouter, RouteComponentProps } from "react-router-dom";

interface Props extends RouteComponentProps<any> {
   /* Parent component's props*/
}

class Parent extends React.Component<Props, {}> {
    render() {
        return <ChildComponent history={this.props.history} />;
    }
}

//Child component related stuff
interface ChildComponentProps extends RouteComponentProps<any> {}

const ChildComponent: React.SFC<ChildComponentProps> = (props) => (
  <div className={styles.body}>
     <div className={styles.cta}>
         <FloatingActionButton onClick={() => history.push(routes[4].path)}>
            <span>Click me</span>
         </FloatingActionButton>
     </div>
   </div>
);

function mapStateToProps(state: types.AppState) {
    /* related code */
}

function mapDispatchToProps(dispatch: Redux.Dispatch<types.AppState>{
    /* related code */
}

export default withRouter(connect(mapStateToProps, mapDispatchToProps)(Parent));

但是,现在我收到以下错误:

Type '{ history: History; }' is not assignable to type 'ChildComponentProps'.
    Property 'match' is missing in type '{ history: History; }'

3 个答案:

答案 0 :(得分:23)

您可以使用RouteComponentProps界面,该界面声明withRouter传递的所有道具:

import { RouteComponentProps } from 'react-router-dom';
..
interface ChildComponentProps extends RouteComponentProps<any> {
  /* other props for ChildComponent */
}
const ChildComponent : React.SFC<ChildComponentProps> = ({ history }) => (
  ..
);

RouteComponentProps的类型参数是paramsmatch属性的类型,因此除非您匹配指定的路径段,否则您将无法使用它。

或者,如果history不是来自withRouter但是自己作为道具传递,则可以从history导入类型:

import { History } from 'history';
..
interface ChildComponentProps {
  history : History
  /* other props for ChildComponent */
}
const ChildComponent : React.SFC<ChildComponentProps> = ({ history }) => (
  ..
);

答案 1 :(得分:6)

我找到的最简单的解决方案

import { RouteComponentProps } from 'react-router-dom';

....

interface Foo{
  history: RouteComponentProps["history"];
  location: RouteComponentProps['location'];
  match: RouteComponentProps['match'];
}

答案 2 :(得分:1)

对于带有钩子的React 16.8:

...
import {withRouter, RouteComponentProps} from 'react-router-dom';
...
const ChildComponent: React.FunctionComponent<RouteComponentProps> = ({history}) => {
...
}