如何从edittext中传递文本作为XML中的参数？

Question

我在不使用Xamarin Android中的wsdl和代理而调用SOAP Web服务。我想从我的edittext中传递用户名和密码作为XML文件中的参数。

这是我的代码：

public void Execute()
        {
            HttpWebRequest request = CreateWebRequest();
            XmlDocument soapenvelopxml = new XmlDocument();
            soapenvelopxml.LoadXml(@"<?xml version=""1.0"" encoding=""utf-8""?>
            <soap:Envelope xmlns:soapenv=""http://schemas.xmlsoap.org/soap/envelope/"" xmlns:ctrm=""http://CTRMService/CTRM"" xmlns:dtom=""http://schemas.datacontract.org/2004/07/DTOModelLayer.DataContracts"">
            <soapenv:Header>
            <DataHeader xmlns='http://CTRMService/CTRM'>AuthenticateUser</DataHeader>
            </soapenv:Header>
            <soap:Body>
            <ctrm:AuthenticateUser>
            <ctrm:request>
            <dtom:Password></dtom:Password>
            <dtom:Username></dtom:Username>
            </ctrm:request>
            </ctrm:AuthenticateUser>
            </soapenv:Body>
            </soapenv:Envelope>");

            using (Stream stream = request.GetRequestStream())
            {
                soapenvelopxml.Save(stream);
             }

            using (WebResponse response = request.GetResponse())
            {
                using (StreamReader rd = new StreamReader(response.GetResponseStream()))
                {

                    string soapresult = rd.ReadToEnd();
}
}
}

我想在<dtom:Password>和<dtom:Username>代码之间传递我的用户名和密码编辑文字中的文字。

Answer 1

string xml = @"<?xml version=""1.0"" encoding=""utf-8""?>
...
<dtom:Username>@username</dtom:Username>
...

xml = xml.Replace("@username", usertext);

soapenvelopxml.LoadXml(xml);