Question

我有一个类似的列表：

var conditions = new PropertyCondition[3];
conditions[0] = new PropertyCondition(AutomationElement.IsEnabledProperty, true);
conditions[1] = new PropertyCondition(AutomationElement.ControlTypeProperty, ControlType.Button);
var conditionEnabledButtons = new AndCondition(conditions);

我想要大写所有字符串，但是当我尝试时：

[['a', 'b', 'null', 'c'], ['d', 'e', '5', 'f'], ['g' ,'h', 'null' ,'I'] ]

我得到了：

x = 0
for row in range(1, sheet.nrows):
    listx.append(sheet.cell(row, x))
    [x.upper() for x in x in listx]
x += 1

我怎样才能发表声明？

Answer 1

此列表理解可以实现，并保留列表结构列表：

listx = [['a', 'b', 'null', 'c'], ['d', 'e', '5', 'f'], ['g' ,'h', 'null' ,'I'] ]

[[x.upper() for x in sublist] for sublist in listx]

返回：

[['A', 'B', 'NULL', 'C'], ['D', 'E', '5', 'F'], ['G', 'H', 'NULL', 'I']]

Answer 2

这就是你要找的东西：

l = [['a', 'b', 'null', 'c'], ['d', 'e', '5', 'f'], ['g' ,'h', 'null' ,'I']]
new_list = []
for row in l:
    new_list.append([x.upper() for x in row])

Python的列表if语句列表

2 个答案: