Question

我想根据最大时间戳获得最低价格。我只是为了把日期从桌子上拿下来。

我的查询应该是：

SELECT min(price) as price, timestamp, resellerid, tableid
        FROM `sql_date_table`
        WHERE tableid=%d
        AND max(timestamp)

任何时候都将不胜感激。谢谢。

编辑：示例数据

tableid | resellerid | price   | timestamp
-----------------------------------------
4           1          1549900   1516405599
4           1          2097042   1518618827
4           1          2107168   1519739181
4           2          1649900   1515352455
4           2          1649900   1518618508
4           2          1649900   1519739180
4           3          1700000   1520962427
4           3          1649900   1519828070
6           2          299400    1519738727
6           3          188800    1520962413
8           1          249900    1518618488
8           2          249500    1518618509

我们的想法是获得“最新爬行”的最低价格

Answer 1

我怀疑你可能想要：

select t.*
from t
where tableid = ?
order by timestamp desc, price asc
limit 1;

Answer 2

试试这个

SELECT * FROM `sql_date_table` WHERE `timestamp`
    IN (SELECT min(`timestamp`) FROM `sql_date_table`
        WHERE `tableid` = ? ORDER BY `price` DESC) LIMIT 1;

Answer 3

这将从每个转销商的最新报价中返回最低价格：

SELECT Min(price)
FROM tab AS t1
JOIN
 (
   SELECT resellerid, Max(timestamp) AS max_ts
   FROM tab 
   GROUP BY resellerid
 ) AS t2
ON t1.timestamp = t2.max_ts

由于您的问题不明确，您可能需要/需要将tableid添加到GROUP BY。

如果您想要额外的列：

SELECT *
FROM tab AS t1
JOIN
 (
   SELECT resellerid, Max(timestamp) AS max_ts
   FROM tab 
   GROUP BY resellerid
 ) AS t2
ON t1.timestamp_ = t2.max_ts
ORDER BY price
LIMIT 1

如果有多个经销商具有相同的价格，则会返回其中一个。

Answer 4

你是什么意思？最大时间戳会多次出现？如果出现问题，使用group by with MIN（）将解决您的问题。

Answer 5

根据最新价格查找经销商中的最低价格：

select resellerid, price, timestamp
from sql_date_table
where 
tableid = ?
and
timestamp = (select max(timestamp)
                   from sql_date_table t2
                   where t2.tableid = sql_date_table.tableid
                   and   t2.resellerid = sql_date_table.resellerid)
order by price limit 1;

OR

select resellerid, price, timestamp
from sql_date_table
where 
tableid = 4
and
timestamp = (select timestamp
                   from sql_date_table t2
                   where t2.tableid = sql_date_table.tableid
                   and   t2.resellerid = sql_date_table.resellerid
                   order by timestamp desc limit 1)
order by price limit 1

根据最大时间戳获得最低价格 - MySQL

5 个答案: