Question

我的桌子是

家长WO

WO     PRICE
1      1790    
1      9

儿童WO

WO     PRICE
1      200    
1      400    
1      600
1      100

我正在尝试这样做

Select  sum(p.price), SUM(c.price) from Parent_WO p
left outer join Child_WO c
on p.WO= c.WO  
group by p.WO

我得到了p.price的错误值。我到7196时应该到1796年。它是父母WO与4孩子WO的总数的多重。

Answer 1

尝试使用2 CTE's;在一个CTE中计算Parent价格，在另一个CTE中计算Child价格并加入结果：

with parent_sum as (
  select
    wo
    ,SUM(price) as ParentSUM
  from parent_wo
  group by wo
)
,child_sum as (
  select
    wo
    ,SUM(price) as ChildSUM
  from child_wo
  group by wo
)
select
  p.wo
  ,ParentSUM
  ,ChildSUM
from parent_sum p
left join child_sum c
  on p.wo = c.wo

Answer 2

在执行sum()之前进行聚合：

Select coalesce(p.wo, c.wo) as wo, sum(p.price), SUM(c.price) from (select p.wo, sum(p.price) as parent_price from Parent_WO p group by p.wo ) p full outer join (select c.wo, sum(c.price) as child_price from Child_WO c group by c.wo ) c on p.WO = c.WO ;

连接表时获取错误的值？

2 个答案: