Question

我试图在python中从字典动态定义变量。我需要将变量作为字符串，它们应该显示为：lightgreen = "#2ecc71".为此，我添加了HEX_VALUE = "'" + HEX_VALUE + "'"但是添加了这个我遇到了错误

> Traceback (most recent call last):
line 22, in <module>
    exec("%s=%s" % (COLOUR_NAME, HEX_VALUE))
  File "<string>", line 1
    darkblue:='#2980b9'
            ^
SyntaxError: invalid syntax

如上所示，这会在变量的第一部分添加'：'，所以我的问题是：如何防止这种情况？

COLOURS = {
    "lightgreen":"'#2ecc71'",
    "darkgreen":"#27ae60",
    "lightblue":"#3498db",
    "darkblue:":"#2980b9",
    "lightpurple":"#e74c3c",
    "darkpurple":"#8e44ad",
    "lightred":"#e74c3c",
    "darkred":"#c0392b",
    "lightorange":"#e67e22",
    "darkorange":"#d35400",
    "lightyellow":"#f1c40f",
    "darkyellow":"#f39c12",
    "lightteal": "#1abc9c",
    "darkteal": "#16a085",
    "lightnavy": "#34495e",
    "darknavy": "#2c3e50"
    }

for COLOUR_NAME, HEX_VALUE in COLOURS.items():
    HEX_VALUE = "'" + HEX_VALUE + "'"
    exec("%s=%s" % (COLOUR_NAME, HEX_VALUE))

Answer 1

正如评论中提到的那样，没有理由使用exec来使python定义新变量。十六进制值已经是字典中的字符串，因此您可以直接访问它们，如下所示：

lightgreen = COLOURS["lightgreen"]

虽然我没有理由定义与dict键同名的变量，因为dict可以在必要时直接访问。

从字典动态定义变量

1 个答案: