我需要为我的收藏分页,我必须应用大量过滤器。但我无法做到这一点。我是laravel的新手所以请告诉我正确的方法。 我的控制器:
//For me it's the best way to look for the value of a spezific column
int seekValue = 5;
foreach (DataGridViewRow row in dataGridView1.Rows)
{
var columnValue = Convert.ToInt32(row.Cells["ColumnName"].Value);
if (columnValue == seekValue)
{
dataGridView1.CurrentCell = row.Cells[0];
}
}
答案 0 :(得分:1)
我遇到过这个问题,为了解决这个问题,我创造了一个名为PaginateCollection的特性:
/*
* Paginate the Laravel Collection before and/or after filtering.
*
*/
trait PaginateCollection
{
/**
* Paginate the collection.
*
* @param \Illuminate\Support\Collection|\Illuminate\Database\Eloquent\Collection $collection
* @param integer $perPage
* @param integer $currentPage
* @return \Illuminate\Pagination\LengthAwarePaginator
*/
public function paginate($collection, $perPage = 10, $currentPage = 1)
{
$offSet = ($currentPage * $perPage) - $perPage;
$otherParams = [
'path' => request()->url(),
'query' => request()->query()
];
return new LengthAwarePaginator(
$collection->forPage(Paginator::resolveCurrentPage() , $perPage),
$collection->count(),
$perPage,
Paginator::resolveCurrentPage(),
$otherParams
);
}
}
也许,这应该会帮助你。