Question

我已经实现了以下代码，将特定文件从zip复制到某个目标目录。

但是这会将整个结构复制到目标目录中。代码是：

import os
import zipfile 

zip_filepath='/home/sundeep/Desktop/SCHEMA AUTOMATION/SOURCE/DSP8010_2017.1.zip'
target_dir='/home/sundeep/Desktop/SCHEMA AUTOMATION/SCHEMA'

with zipfile.ZipFile(zip_filepath) as zf:
    dirname = target_dir
    zf.extract('DSP8010_2017.1/json-schema/AccountService.json',path=dirname)

我的问题是如何只将AccountService.json文件复制到目标目录，而不是整个结构。通过实施shutil的任何可能性？

Answer 1

您可以将文件名添加到现有目录中，如下所示： -

a = 'DSP8010_2017.1/json-schema/AccountService.json'
dirname = target_dir+"/"+(a.split('/')[-1])

正如您所说的有问题，您可以尝试这样： -

import zipfile

zip_filepath='/home/sundeep/Desktop/SCHEMA AUTOMATION/SOURCE/DSP8010_2017.1.zip'
target_dir='/home/sundeep/Desktop/SCHEMA AUTOMATION/SCHEMA'

fantasy_zip = zipfile.ZipFile(zip_filepath)
file = fantasy_zip.extract('AccountService.json', zip_filepath)
target_dir = target_dir+"/"+file 
fantasy_zip.close()

Answer 2

试试这个： -

import zipfile


zip_filepath='/home/sundeep/Desktop/SCHEMA AUTOMATION/SOURCE/DSP8010_2017.1.zip'

target_dir='/home/sundeep/Desktop/SCHEMA AUTOMATION/SCHEMA'


with zipfile.ZipFile(zip_filepath) as zf:

       for file in zf.namelist():

            if file.endswith("AccountService.json"):
                zf.extract(file,target_dir)

Answer 3

import os
import shutil
import zipfile

zip_filepath='/home/sundeep/Desktop/SCHEMA AUTOMATION/SOURCE/DSP8010_2017.1.zip'
target_dir='/home/sundeep/Desktop/SCHEMA AUTOMATION/SCHEMA'


with zipfile.ZipFile(zip_filepath) as z:
    with z.open('DSP8010_2017.1/json-schema/AccountService.json') as zf, open(os.path.join(target_dir, os.path.basename('AccountService.json')), 'wb') as f:
        shutil.copyfileobj(zf, f)

从zip中提取某些文件但不是完整目录

3 个答案: