Question

我正在为我的孩子创建一个flashcard游戏。它关于迪诺斯。我无法制作＆＃34;恭喜，你做对了＆＃34;出现在屏幕上。我把代码移到了所有地方，但没有运气。有人可以帮帮我吗。

要清楚，我想要发生的是当用户按下键盘上的数字1,2,3时，如果该键是与问题相关的正确答案，则消息＆＃34;恭喜，你做对了！＆＃34;应出现在屏幕上。

我知道keydown事件现在是返回键，但我这样做仅用于测试目的。对于testtext变量，这也是相同的。我正在使用该变量来查看是否可以打印＆＃34; Hello WOrld＆＃34;到了屏幕。

我确实感觉它与正在运行的循环有关。我的猜测是，它确实出现了几分之一秒，但在任何人都能看到它之前消失了。

import pygame, random

pygame.font.init()
pygame.init()

font = pygame.font.Font(None, 48)
#Created the window display
size = width, height = 800,800
screen = pygame.display.set_mode(size)
#Loads the images of the starting game Trex
#t_rex = pygame.image.load('trex1.png')
##Places the image on the screen
#screen.blit(t_rex,(150,50))



count = 0
score = 0
active = False

testtext = font.render("Hello WOrld", True, (250, 250, 250))







#The below code keeps the display window open until user decides to quie app


crashed = False
while not crashed:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            crashed = True
        if event.type==pygame.KEYDOWN:
            if event.key==pygame.K_RETURN:
                screen.blit(testtext, (200,699))

    while count < 2:
        screen.fill(0)

        dinoQuestions = ["Does a t-rex eat meat?\n","Does a trycerotopes have 3 horns?\n"]

        dinoAnswer = ["Yes\n", "No\n","Maybe\n"]

        wordnum = random.randint(0, len(dinoQuestions)-1)

        mainpic = pygame.image.load("trex1.png")

        screen.blit(mainpic, (150, 20))

        options = [random.randint(0, len(dinoAnswer)-1),random.randint(0, len(dinoAnswer)-1)]

        options[random.randint(0,1)] = wordnum

        question_display = font.render(dinoQuestions[wordnum].rstrip('\n'),True, (255, 255, 255))
        text1 = font.render('1 - ' + dinoAnswer[options[0]].rstrip('\n'),True, (255, 255, 255))
        text2 = font.render('2 - ' + dinoAnswer[options[1]].rstrip('\n'),True, (255, 255, 255))

        #the below code is for testing purposes only


        screen.blit(question_display,(200, 590))
        screen.blit(text1, (200, 640))
        screen.blit(text2, (200, 690))


        count = count + 1
        pygame.display.flip()

Answer 1

当您稍后致电screen.fill(0)时，处理返回按键事件时您执行的屏幕表面的blit会被覆盖。

我已经重新安排了一些代码并添加了在适当的按键上显示结果。

import pygame
import random

pygame.init()
pygame.font.init()

font = pygame.font.Font(None, 48)
size = width, height = 800,800
screen = pygame.display.set_mode(size) #Created the window display
count = 0
score = 0
active = False

white = pygame.color.Color("white")
black = pygame.color.Color("black")
green = pygame.color.Color("green")

# load/create static resources once
mainpic = pygame.image.load("trex1.png")

testtext = font.render("Hello World", True, (250, 250, 250))
correct_text = font.render("Correct! Well Done!", True, green)

clock = pygame.time.Clock() # for limiting FPS

dinoQuestions = ["Does a t-rex eat meat?","Does a triceratops have 3 horns?"]
dinoAnswer = ["Yes", "No","Maybe"]

# initialise state
show_hello = False
show_correct = False
update_questions = True  # need to update questions on the first iteration
finished = False

while not finished:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            finished = True
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_RETURN:
                show_hello = not show_hello # toggle flag for later display
            elif event.key == pygame.K_SPACE:
                update_questions = True
            elif event.key in [pygame.K_1, pygame.K_2]:
                # an answer has been selected
                # pygame.K_1 is 0, pygame.K_2 is 1
                if dinoAnswer[event.key - pygame.K_1] == "Yes":
                    show_correct = True
                    count += 1
                else:
                    show_correct = False

    screen.fill(black)
    screen.blit(mainpic, (150, 20))
    if show_hello:
        screen.blit(testtext, (200,199))

    if show_correct:
        screen.blit(correct_text, (200, 300))

    if update_questions:
        random.shuffle(dinoQuestions)
        random.shuffle(dinoAnswer)
        question_display = font.render(dinoQuestions[0],True, white)
        text1 = font.render('1 - ' + dinoAnswer[0],True, white)
        text2 = font.render('2 - ' + dinoAnswer[1],True, white)
        update_questions = False
        show_correct = False

    # Display the Question
    screen.blit(question_display,(200, 590))
    screen.blit(text1, (200, 640))
    screen.blit(text2, (200, 690))
    # count = count + 1
    pygame.display.flip()
    clock.tick(60)

希望这足以让你扩展一个框架。

如果您对代码的任何部分有任何疑问，请与我们联系。

Answer 2

我对你的确切问题感到有点困惑，所以我将尝试回答。你说你想要单词＆＃34;恭喜，你说对了！＆＃34;，所以我可以帮助你解决问题所在。在为屏幕着色之前，你会对测试文本进行blit，因此每次循环循环时，它都会显示testtext，但几乎可以立即用screen.fill（0）覆盖它。为了使它更好，你应该在屏幕着色后放置文本的blitting。执行此操作的最佳方法是在循环开始时将其放置，或者在屏幕的当前位置之后创建另一个事件检测器。填写代码。此外，我将摆脱堆叠的while循环，而是用if语句替换它，因为它已经在while循环中。这是你在找什么？

如何在点击返回键后显示字符串

2 个答案: