Question

在美国东部时间每周五每周五下午6点开始一个小项目，给予新的特殊奖励并重置游戏。

实施例：每周五美国东部时间下午6点，特别优惠将重置并推出新的优惠。我想做的就是让我们说星期二，我想知道有多少天：小时：分钟：秒到美国东部时间星期五6点。

我现在的代码可以使用，但问题是我必须手动更新下周五的日期。

import datetime
today = datetime.datetime.today()
reset = datetime.datetime(2018, 3, 18, 18, 00, 00)
print(reset-today)

在18日之后，我必须手动输入下周五的日期，我该如何自动进行？

Answer 1

可能不是最优雅的方式，但这应该有帮助..

import datetime

#import relativedelta module, this will also take into account leap years for example..
from dateutil.relativedelta import relativedelta

#Create a friday object..starting from todays date
friday = datetime.datetime.now()

#Friday is day 4 in timedelta monday is 0 and sunday is 6.  If friday is 
#today it will stop at today..

#If it is friday already and past 18:00, add 7 days until the next friday. 
if friday.hour > 18:
    next_week = datetime.timedelta(7)
    friday = friday - next_week
#else iterate though the days until you hit the first Friday.
else:
    while friday.weekday() != 4:
        friday += datetime.timedelta(1)

#the date will now be the first Friday it comes to, so replace the time.
friday = friday.replace(hour=18, minute=00, second=00)

#create a date for today at this time
date_now = datetime.datetime.now()
>>>2018-03-17 04:54:34.974214

# calculate using relativedelta
days_til_next_fri = relativedelta(friday, date_now)

print("The Time until next friday 18:00 is {} days {} hours {} minutes and {} seconds".format(days_til_next_fri.days, days_til_next_fri.hours, days_til_next_fri.minutes, days_til_next_fri.seconds))

>>>The Time until next friday 18:00 is 6 days 13 hours 50 minutes and 15 seconds

如何使用datetime自动更改给定的日期和时间

1 个答案: