Question

字典将存储电影的名称，对于每部电影，字典值将是显示时间列表。

我无法理解。这是正确的吗？

movie A: 9,11,15 movie B: 10,14,6 movie C: 11,13,19

dictionary={"moviesA":0, "moviesB":0, "moviesC":0}

showingtimes={"moviesA": 9, "moviesA": 11, "moviesA": 15, "moviesA": 21, "moviesB" : 10, "moviesB": 14, "moviesB": 16,
              "moviesC": 11, "moviesC":13, "moviesC":19, "moviesC": 20, "moviesC": 21, "movieC":22}

Answer 1

使用list存储您的放映时间。您的词典的key将是电影的名称，其value是放映时间列表。

d["movieA"] = [9, 11, 13, 15]
d["movieB"] = [13, 17]

Answer 2

将其存储起来：

data1={'movie A': [9,11,15], 'movie B': [10,14,6], 'movie C': [11,13,19]}

现在，如果你想按时间检查，你可以这样做：

#which movies shows available at 11 ?

def check_by_time(time_mo):
    movies_list=[]
    for i, j in data1.items():
        if time_mo in j:
            movies_list.append(i)
    return movies_list
print(check_by_time(11))

输出：

['movie A', 'movie C']

在python中使用字典创建电影院

2 个答案: