我正在尝试在Google Firebase中创建一个节点,并使用其唯一ID在同一名称的Google Firestore中创建一个文档。
我正在使用Google的PHP Firestore客户端:https://github.com/GoogleCloudPlatform/google-cloud-php-firestore
我已经阅读了他们的文档:http://googlecloudplatform.github.io/google-cloud-php/#/docs/cloud-firestore/v0.5.1/firestore/writebatch
这是我的代码:
<?php
use \Google\Cloud\Firestore\FirestoreClient;
use \Google\Cloud\Core\Timestamp;
use \Google\Cloud\Firestore\Transaction as FirestoreTransaction;
use \grptx\Firebase as FirebaseClient;
class FirestoreTest
{
public function create()
{
$client = new FirebaseClient();
$database = $client->getDatabase();
$org = array(
"acl" => array(),
"people" => array()
);
$ref = $database->getReference("/clients/")->push($org);
$key = $ref->getKey();
$config = array(
"projectId" => "xxx",
"keyFile" => json_decode(file_get_contents("/xxx/firebase_auth.json"), true)
);
$firestore = new FirestoreClient($config);
$batch = $firestore->batch();
$batch->create("/clients/".$key, [
'organization_ID' => $key
]);
print_r($key); // this key gets generated, no errors occur.
}
}
这是我正在使用的PHP版本:
php -v
PHP 7.1.10-1+ubuntu14.04.1+deb.sury.org+1 (cli) (built: Sep 29 2017 17:33:22) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2017 Zend Technologies
with Zend OPcache v7.1.10-1+ubuntu14.04.1+deb.sury.org+1, Copyright (c)
1999-2017, by Zend Technologies
答案 0 :(得分:0)
您可能不需要为一次写入编写批处理:
$docRef = $firestore->collection('clients')->document($key);
$docRef->set(['organization_ID' => $key]);
另外,查看文档。我们添加了PHP样本:
https://cloud.google.com/firestore/docs/manage-data/add-data