Question

我希望实现一项功能，使用户能够按位置过滤/获取业务。这是我的逻辑：

声明一个变量来保存已过滤的数组
循环业务
如果查询未定义
调用商家的过滤方法
如果查询等于数据库中可用的位置
将具有指定位置的商家推入数组
使用

指定的位置或带有相应状态代码的错误消息。

This is the mock database:
const businesses = [
  {
    id: 1,
    businessName: 'Kulikuli and Sons Limited',
    description: 'We take you to heaven and back',
    email: 'kososhi@gmail.com',
    location: 'Kaduna',
    category: 'Hospitality',
    phoneNumber: '07033288342'
  },

  {
    id: 2,
    businessName: 'Rochas Limited',
    description: 'We satisfy all your maintenance',
    email: 'rochas2u@gmail',
    location: 'Lagos',
    category: 'Repairs and Maintenance',
    phoneNumber: '07033288341'
  },

  {
    id: 3,
    businessName: 'Lekoto Travels',
    description: 'Travel with us and you won\'t regret it',
    email: 'lekotoboss@gmail.com',
    location: 'Kaduna',
    category: 'Travels and Tours',
    phoneNumber: '07033288344'
  },
];

This is the method to control the route: GET /businesses?location=<location>
static filterByLocation(req, res) {
    const filteredLocation = [];
    for (let i = 0; i < businesses.length; i += 1) {
      if (typeof req.query.location !== 'undefined') {
        businesses.filter((business) => {
          if (business.location === req.query.location) {
            filteredLocation.push(business);
          }
        });
      }
      return res.status(200).send({
        status: 'Success',
        location: filteredLocation
      });
    }
    return res.status(404).send({
      status: 'Fail',
      message: 'Location not found'
    });
  }
However, the code isn't working as expected. Where am I getting it wrong?

Answer 1

试试这个，Filter函数返回过滤结果不需要根据条件推入数组，而res.send不返回JSON所以你必须使用res.json（）或res.send（JSON.stringify（json））。你正在返回内部for循环的响应，这将无效。

static filterByLocation(req, res) {
    const filteredLocation = businesses.filter((business) => {
        return business.location === req.query.location;
    });
    if (filteredLocation.length !== 0)
        return res.status(200).json({
            status: 'Success',
            location: filteredLocation
        });
    return res.status(404).json({
        status: 'Fail',
        message: 'Location not found'
    });
}

我哪里弄错了？

1 个答案: