Question

我是bash编程的新手，我正在尝试设置一个bash脚本，我需要存储脚本路径的值，但正如我所看到的，它会丢失。

#!/bin/bash

dir = "$( cd "$( dirname "${BASH_SOURCE[0]}"  )" && pwd  )"

echo "$dir"

echo "
|------------------------------------|
|------------------------------------|
|                                    |
|Welcome to ec2 setup!!! Let's begin |
|                                    |
|------------------------------------|
|------------------------------------|
"

echo "
/-----------------------------

Do you want to install nodejs?

-----------------------------/"
select yn in "Yes" "No"; do
    case $yn in
        Yes ) echo "Enter the version number, eg; 8, 9"
            read version
            curl -sL https://deb.nodesource.com/setup_$version.x | sudo -E bash
            sudo apt-get install -y nodejs
            echo "Node version installed is $(node -v)"; break;;
        No ) break;;
    esac

    done

echo "$dir"

echo "
/-----------------------------

Do you want to install mongodb?

-----------------------------/"

select yn in "Yes" "No"; do
    case $yn in
        Yes ) sudo apt-key adv --keyserver hkp://keyserver.ubuntu.com:80 --recv 2930ADAE8CAF5059EE73BB4B58712A2291FA4AD5
            echo "deb [ arch=amd64,arm64 ] https://repo.mongodb.org/apt/ubuntu xenial/mongodb-org/3.6 multiverse" | sudo tee /etc/apt/sources.list.d/mongodb-org-3.6.list
            sudo apt-get update
            sudo apt-get install -y mongodb-org
            sudo service mongod start; break;;
        No ) break;;
    esac
done

echo "$dir"

当我运行此脚本时，echo "$dir"不打印任何内容，除非在脚本的开头。

我在这里错过了什么？

此外，稍后在代码中，我必须更改目录，那么如何维护对初始目录的引用呢？

Answer 1

变量名称和=之间的变量声明中不能包含空格，

DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd)"

Bash：保留变量中脚本的路径

1 个答案: