Question

我如何：

确定数据框df中的哪个项目属于每个列表（list1或list2）
创建新列（'new_item'）
确定应将哪个变量附加到“item”值并将其添加到新列

两个独特项目清单：

twentysix_above = '_26+' (value is equal or greater than 26)
six_to_twentyfive = '_25'  (value is between 6 and 25)
one_to_five = '_5'  (value is between 1 and 5)

如果item在list1中，请将以下变量值附加到项目的末尾，并将其附加到“new_item”列：

twentyone_above = '_21+' (value is equal or greater than 21)
one_to_twenty = '_20' (value is between 1 and 20)

如果item在list2中，请将以下变量值附加到每个项目的末尾，并将其附加到“new_item”列：

>> print df
    item    number
0   one     4
1   door    55
2   sun     2
3   tires   62
4   tires   7
5   water   94

>> list1 = ['one','two','shoes']
>> list2 = ['door','four','tires']
>> df['match'] = df.item.isin(list1)
>> bucket = []
>> for row in df.itertuples():
        if row.match == True and row.item > 25:
            bucket.append(row.item + '_26+')
        elif row.match == True and row.item >5:
            bucket.append(row.item + '_25')
        elif row.match == True and row.item >0:
            bucket.append(row.item +'_5')                    
        else:
            bucket.append(row.item)
        df['new_item'] = bucket

>> print df
    item    number  match   new_item
0   one     4       True    one_5
1   door    55      True    door
2   sun     2       False   sun
3   tires   62      True    tires
4   tires   7       True    tires
5   water   94      False   water

如果该项目不在任一列表中，请将项目名称移至“new_item”列。

Dataframe列将包含其中每个列表中的一个，一些或没有“items”以及“number”列中的关联数字。我已经部分到了，但我不确定如何与其他列表进行比较并将其全部放入'new_item'列？任何帮助表示赞赏，谢谢！

    item    number  new_item
0   one     4       one_20
1   door    55      door__21+
2   sun     2       sun
3   tires   62      tires_21
4   tires   7       tires_20
5   water   94      water

所需结果:(比较两个列表，可能不需要布尔检查列）

accountDelete(id, name) {
    let accountsToAdd = this.userForm.value.accountsToAdd;
    const accountsToDelete = this.userForm.value.accountsToDelete;
    accountsToDelete.push(
        {
            id: id,
            name: name
        }
    );
    console.log(accountsToDelete);
    accountsToAdd = accountsToAdd.filter(account => account.id !== id);
    console.log(accountsToAdd);
}

Answer 1

看起来你想要的结果有点偏。第一行在列表一中，其值为4，因此它应该是＆＃39; one_5＆＃39;正确？

无论如何，这可以通过布尔掩码实现。 DataFrames有一个有用的isin（）函数，可以很容易地找到值是否在列表中。那么你还有两个条件，如果你需要两个数字之间的值，或者如果范围是无界的则只需要一个条件。

import pandas as pd
import numpy as np
df = pd.DataFrame({'item': ['one', 'door', 'sun', 'tires', 'tires', 'water'], 
                   'number': [4, 55, 2, 62, 7, 94]})
list1 = ['one','two','shoes']
list2 = ['door','four','tires']

df['new_item'] = df['item']
logic1 = np.logical_and(df.item.isin(list1), df.number > 25)
logic2 = np.logical_and.reduce([df.item.isin(list1), df.number > 5, df.number <= 25])
logic3 = np.logical_and.reduce([df.item.isin(list1), df.number > 1, df.number <= 5])
logic4 = np.logical_and(df.item.isin(list2), df.number >= 21)
logic5 = np.logical_and.reduce([df.item.isin(list2), df.number > 1, df.number < 20])

df.loc[logic1,'new_item'] = df.loc[logic1,'item']+'_26+'
df.loc[logic2,'new_item'] = df.loc[logic2,'item']+'_25'
df.loc[logic3,'new_item'] = df.loc[logic3,'item']+'_5'
df.loc[logic4,'new_item'] = df.loc[logic4,'item']+'_21+'
df.loc[logic5,'new_item'] = df.loc[logic5,'item']+'_20'

我们将此作为输出

如何将两个列表与python元组进行比较，识别项目，并根据条件附加值？

1 个答案: