我有一张表格,上面有卖车的详情。其中一些汽车已在最近1年,2年或3年内转售。该表如下所示:
Car_Type || Car_Reg_No || Sold_Date || Listing_No
Hatch || 23789 || 2017-02-03 11:26 || X6529
Coupe || 16723 || 2016-11-07 09:40 || N8156
Sedan || 35216 || 2016-05-23 10:34 || M8164
Hatch || 23789 || 2016-09-16 04:30 || O7361
现在,我需要查询在最近的销售日期后1年内重新销售的记录(汽车)以及销售的次数。所以,我的输出将是这样的:
Car_Type || Car_Reg_No || Sold_Count || Latest_Sold_Date
Hatch || 23789 || 2 || 2017-02-03 11:26
从本质上讲,如何在最近售出日期的特定时间范围内检查重新销售的记录?
答案 0 :(得分:1)
您可以通过查找最大值并根据您的条件加入来实现此目的。
declare @TableA table (Car_Type varchar(64)
,Car_Reg_No int
,Sold_Date datetime
,Listing_No varchar(6))
insert into @TableA
values
insert into @TableA
values
('Hatch',23789,'2017-02-03 11:26','X6529'),
('Coupe',16723,'2017-11-07 09:40','N8156'),
('Sedan',35216,'2017-05-23 10:34','M8164'),
('Hatch',23789,'2016-09-16 04:30','O7361'),
('Coupe',16723,'2014-11-07 09:40','N8156')
;with cte as(
select
Car_Type
,Car_Reg_No
,Latest_Sold_Date = max(Sold_Date)
from
@TableA
group by
Car_Type
,Car_Reg_No)
select
a.Car_Type
,a.Car_Reg_No
,Sold_Count = count(b.Listing_No) + 1
,a.Latest_Sold_Date
from cte a
inner join
@TableA b on
b.Car_Reg_No = a.Car_Reg_No
and b.Sold_Date != a.Latest_Sold_Date
and datediff(day,b.Sold_Date,a.Latest_Sold_Date) < 366
--if you want only cars which were sold within last year too, uncomment this
--and datediff(day,a.Latest_Sold_Date,getdate()) < 366
group by
a.Car_Type
,a.Car_Reg_No
,a.Latest_Sold_Date
答案 1 :(得分:0)
根据我的理解..,
select sd1.Car_Type, sd1.Car_Reg_No,
count(sd1.Car_Reg_No) + 1 'no of sales in last one year', --1 is added because, see the last condition
sd1.Sold_Date 'Last sold date'
from(
select *,ROW_NUMBER() over(partition by Car_Reg_No order by sold_date desc) as rn from #Table) as sd1
join
(select * from #Table) as sd2
on sd1.Car_Type = sd2.Car_Type
and DATEDIFF(dd,sd2.Sold_Date,sd1.Sold_Date) < 366
and sd1.rn = 1
and sd1.Sold_Date <> sd2.Sold_Date -- here last sold is eliminated. so count is added by one.
group by sd1.Car_Type,sd1.Sold_Date, sd1.Car_Reg_No
order by sd1.Car_Reg_No