我有一个类“用户”有一些请求。每个请求都有2个用户（发件人和收件人）：
public class User {
@OneToMany(mappedBy = "?")
private List<Request> requests;
}
public class Request{
@ManyToOne ?
private User sender;
@ManyToOne ?
private User receiver;
}
我如何映射这个？
答案 0 :(得分：1)
namespace BlueMine.Data
{
public class SqlGuid
: System.IComparable
, System.IComparable<SqlGuid>
, System.Collections.Generic.IComparer<SqlGuid>
, System.IEquatable<SqlGuid>
{
private const int NUM_BYTES_IN_GUID = 16;
// Comparison orders.
private static readonly int[] m_byteOrder = new int[16] // 16 Bytes = 128 Bit
{10, 11, 12, 13, 14, 15, 8, 9, 6, 7, 4, 5, 0, 1, 2, 3};
private byte[] m_bytes; // the SqlGuid is null if m_value is null
public SqlGuid(byte[] guidBytes)
{
if (guidBytes == null || guidBytes.Length != NUM_BYTES_IN_GUID)
throw new System.ArgumentException("Invalid array size");
m_bytes = new byte[NUM_BYTES_IN_GUID];
guidBytes.CopyTo(m_bytes, 0);
}
public SqlGuid(System.Guid g)
{
m_bytes = g.ToByteArray();
}
public byte[] ToByteArray()
{
byte[] ret = new byte[NUM_BYTES_IN_GUID];
m_bytes.CopyTo(ret, 0);
return ret;
}
int CompareTo(object obj)
{
if (obj == null)
return 1; // https://msdn.microsoft.com/en-us/library/system.icomparable.compareto(v=vs.110).aspx
System.Type t = obj.GetType();
if (object.ReferenceEquals(t, typeof(System.DBNull)))
return 1;
if (object.ReferenceEquals(t, typeof(SqlGuid)))
{
SqlGuid ui = (SqlGuid)obj;
return this.Compare(this, ui);
} // End if (object.ReferenceEquals(t, typeof(UInt128)))
return 1;
} // End Function CompareTo(object obj)
int System.IComparable.CompareTo(object obj)
{
return this.CompareTo(obj);
}
int CompareTo(SqlGuid other)
{
return this.Compare(this, other);
}
int System.IComparable<SqlGuid>.CompareTo(SqlGuid other)
{
return this.Compare(this, other);
}
enum EComparison : int
{
LT = -1, // itemA precedes itemB in the sort order.
EQ = 0, // itemA occurs in the same position as itemB in the sort order.
GT = 1 // itemA follows itemB in the sort order.
}
public int Compare(SqlGuid x, SqlGuid y)
{
byte byte1, byte2;
//Swap to the correct order to be compared
for (int i = 0; i < NUM_BYTES_IN_GUID; i++)
{
byte1 = x.m_bytes[m_byteOrder[i]];
byte2 = y.m_bytes[m_byteOrder[i]];
if (byte1 != byte2)
return (byte1 < byte2) ? (int)EComparison.LT : (int)EComparison.GT;
} // Next i
return (int)EComparison.EQ;
}
int System.Collections.Generic.IComparer<SqlGuid>.Compare(SqlGuid x, SqlGuid y)
{
return this.Compare(x, y);
}
public bool Equals(SqlGuid other)
{
return Compare(this, other) == 0;
}
bool System.IEquatable<SqlGuid>.Equals(SqlGuid other)
{
return this.Equals(other);
}
}
}
内sender和receiver需要两个引用。
User