Question

我需要拥有默认铃声的URI。

我可以使用此代码

获得默认铃声

import { Component, NgModule, VERSION } from '@angular/core';
import { BrowserModule } from '@angular/platform-browser';
import { Observable } from 'rxjs/Observable';
import { Subject } from 'rxjs/Subject';
import 'rxjs/add/operator/filter';
import 'rxjs/add/operator/do';
import 'rxjs/add/operator/switchMap';

@Component({
  selector: 'my-app',
  template: `
    <button (click)="model.on = !model.on; userClick$.next()">{{ model.on ? 'Stop' : 'Start' }}</button>
    <h1>Numbers stream</h1>
    <div *ngFor="let numberValue of (numbers$ | async)">
      <h2>{{ numberValue }}</h2>
    </div>
    <label>{{ model.log }}</label>
  `,
})
export class App {
  model = {
    on: false,
    log: ''
  }
  userClick$ = new Subject<void>();
  numbers$: Observable<number[]> = this.userClick$
    .filter(() => !!this.model.on)
    .do(() => this.model.log = '')
    .switchMap(() => this.getRandomNumber())
    .switchMap((num) => this.getExpNumber(num))
    .switchMap((num) => this.getFloor(num))
    .switchMap((num) => this.getCeil(num));
  constructor() {
  }
  /**
   * Runs after user click
   */
  getRandomNumber(): Observable<number[]> {
    return new Observable<number[]>(observer => {
      this.model.log += ' getRandomNumber';
      observer.next([Math.floor(Math.random() * 10) + 1]);

      return () => {}
    }
  }
  /**
   * Depends on getRandomNumber and run after it
   */
  getExpNumber(n: number): Observable<number[]> {
    return new Observable<number[]>(observer => {
      this.model.log += ' getExpNumber';
      observer.next([Math.floor(Math.exp(n)]);

      return () => {}
    }
  }
  /**
   * Runs in parallel with getCeil
   */
  getFloor(n: number): Observable<number[]> {
    return new Observable<number[]>(observer => {
      this.model.log += ' getFloor';
      observer.next([Math.floor(n)]);

      return () => {}
    }
  }
  /**
   * Runs in parallel with getFloor
   */
  getCeil(n: number): Observable<number[]> {
    return new Observable<number[]>(observer => {
      this.model.log += ' getCeil';
      observer.next([Math.ceil(n)]);

      return () => {}
    }
  }
}
@NgModule({
  imports: [ BrowserModule ],
  declarations: [ App ],
  bootstrap: [ App ]
})
export class AppModule {}

在rt（铃声）中，我可以在截图中看到mUri，但它不是公共财产，所以我不能拥有它。

我怎么能拥有这个属性？

注意：RingtoneManager.java中有一个getUri，但它是隐藏的。

            Uri uri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_RINGTONE);
            Ringtone rt = RingtoneManager.getRingtone(context,uri);

Answer 1

String directoryName = null;
            try {
                directoryName = "/parent_folder/sub-folder/";
                String filePath = new File("").getAbsolutePath();
                filePath.concat(directoryName);
                File directory = new File(filePath);
                if (! directory.exists()){
                    boolean created = directory.mkdirs();
                    if (!created) {
                      //TODO: add your code here
                    }
                }
            } catch (Exception e) {
                e.printStackTrace();
            }

Answer 2

A &a = b;

希望这适合你！：）

我怎样才能获得默认铃声uri

2 个答案: