SQL脚本错误

Question

我对此脚本有疑问：

    UPDATE Orders AS o 
    SET o.menuId = 14259 
    WHERE o.menuId = 14422 
    AND o.userId = 
    (SELECT Id FROM users where Group = 
    (SELECT Id FROM groups where eatGroupId = 4))

错误：子查询返回超过1行//因为有许多组和用户。有谁知道它是否有可能使这个查询有效？或其他替代方案？

Answer 1

{{1}}

Answer 2

修改您的查询以更新第4组下的所有用户：

UPDATE Orders AS o 
SET o.menuId = 14259 
WHERE o.menuId = 14422 
AND o.userId IN 
(SELECT Id FROM users where Group = 
(SELECT Id FROM groups where eatGroupId = 4))

或更新前1行使用：

UPDATE Orders AS o 
SET o.menuId = 14259 
WHERE o.menuId = 14422 
AND o.userId = 
(SELECT TOP 1 Id FROM users where Group = 
(SELECT TOP 1 Id FROM groups where eatGroupId = 4))

Answer 3

使用IN运算符，该运算符允许WHERE cluase中的多个值并执行子查询中的JOIN

UPDATE Orders 
SET menuId = 14259 
WHERE menuId = 14422 AND 
userId IN (
    SELECT u.Id FROM users u
    INNER JOIN groups g ON g.Id= u.Group
    WHERE g.eatGroupId = 4)

Answer 4

您可以尝试使用此代码

 UPDATE Orders AS o 
    SET o.menuId = 14259 
    WHERE o.menuId = 14422 
    AND o.userId = 
    (SELECT Id FROM users where Group = 
    (SELECT Id FROM groups where eatGroupId = 4 group by Id) group by Id)

Answer 5

谢谢大家的回答。我希望它会对某人有所帮助。

  UPDATE Orders AS o 
    JOIN users u on u.Id=o.userId
    JOIN groups g on g.Id=u.Group
    SET o.menuId = 14259
    WHERE o.menuId = 14422 
    AND g.eatGroupId = 4;