Question

注意第二行到最后一行的连接＆＃39; \ n＆＃39;。它似乎被添加到字符串的一部分而不是像我想要的那样充当换行符。

关于我做错了什么的想法？

我试图在在线编码练习环境中展示这一点。没有涉及HTML。

  <html>       
   <head>
      <title>Paging Using PHP</title>
   </head>

   <body>
      <?php
         $dbhost = 'localhost:3036';
         $dbuser = 'root';
         $dbpass = 'password';

         $rec_limit = 10;
         $conn = mysql_connect($dbhost, $dbuser, $dbpass);

         if(! $conn ) {
            die('Could not connect: ' . mysql_error());
         }
         mysql_select_db('test_db');

         /* Get total number of records */
         $sql = "SELECT * FROM trail101 WHERE activities IN(\'Murals\',\'Concert\',\'Theater\',\'Museums\') ORDER BY id";
         $retval = mysql_query( $sql, $conn );

         if(! $retval ) {
            die('Could not get data: ' . mysql_error());
         }
         $row = mysql_fetch_array($retval, MYSQL_NUM );
         $rec_count = $row[0];

         if( isset($_GET{'page'} ) ) {
            $page = $_GET{'page'} + 1;
            $offset = $rec_limit * $page ;
         }else {
            $page = 0;
            $offset = 0;
         }

         $left_rec = $rec_count - ($page * $rec_limit);
         $sql = "SELECT *  ". 
            "FROM trail101 ".
            "WHERE activities IN(\'Murals\',\'Concert\',\'Theater\',\'Museums\') ORDER BY id ".
            "LIMIT $offset, $rec_limit";

         $retval = mysql_query( $sql, $conn );

         if(! $retval ) {
            die('Could not get data: ' . mysql_error());
         }

         while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
            echo "ID :{$row['id']}  <br> ".
               "ACTIVITY NAME : {$row['activity_name']} <br> ".
               "--------------------------------<br>";
         }

         if( $page > 0 ) {
            $last = $page - 2;
            echo "<a href = \"$_PHP_SELF?page = $last\">Last 10 Records</a> |";
            echo "<a href = \"$_PHP_SELF?page = $page\">Next 10 Records</a>";
         }else if( $page == 0 ) {
            echo "<a href = \"$_PHP_SELF?page = $page\">Next 10 Records</a>";
         }else if( $left_rec < $rec_limit ) {
            $last = $page - 2;
            echo "<a href = \"$_PHP_SELF?page = $last\">Last 10 Records</a>";
         }

         mysql_close($conn);
      ?>

   </body>
</html>

Answer 1

\n可以帮助您在输入框的值中添加换行符，但不会在innerHTML或textContent中添加换行符。

使用</br>代替

outputString += list[i] + '</br>';

Javascript / n显示为字符串的一部分

1 个答案: