Question

我不知道如何做到这一点，所以任何帮助将不胜感激。我有两个想要组合成一个对象的对象。我已经使用了扩展运算符来执行此操作：

newObj = {...obj1, ...obj2};

这个，例如给我这个：

{
  [
    obj1A{
     "item": "stuff",
     "item": "stuff"
    },
    obj1B{
     "item": "stuff",
     "item": "stuff"
    }
  ],
  [
    obj2A{
     "item": "stuff",
     "item": "stuff"
    },
    obj2B{
     "item": "stuff",
     "item": "stuff"
    }
  ]
}

但我想要的是：

 {
      [
        obj1A{
         "item": "stuff",
         "item": "stuff"
        },
        obj1B{
         "item": "stuff",
         "item": "stuff"
        },
        obj2A{
         "item": "stuff",
         "item": "stuff"
        },
        obj2B{
         "item": "stuff",
         "item": "stuff"
        }
      ]
    }

任何人都知道怎么做？

Answer 1

使用正确的唯一名称，您可以使用Object.assign并创建新对象。

＆＃13;

var object1 = { obj1A: { item1: "stuff", item2: "stuff" }, obj1B: { item1: "stuff", item2: "stuff" } },
    object2 = { obj2A: { item1: "stuff", item2: "stuff" }, obj2B: { item1: "stuff", item2: "stuff" } },
    combined = Object.assign({}, object1, object2);
  
console.log(combined);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 2

如果你正在使用jQuery，你可以做类似于https://jsfiddle.net/d11kfd4d/的事情：

var a = { 
   propertyOne: 'One',
   propertyTwo: 'Two'
};

var b = { 
   propertyThree: 'Three',
   propertyFour: 'Four'
}

var c = $.extend(a, b);

console.log(c);

Answer 3

假设你有一个拼写错误（将此[]更改为此{}）并且键是valids（不重复），则可以使用Spread语法。

var obj1 = { obj1A: { item: "stuff", item2: "stuff" }, obj1B: { item: "stuff", item2: "stuff" } },
    obj2 = { obj2A: { item: "stuff", item2: "stuff" }, obj2B: { item: "stuff", item2: "stuff" } }
    
console.log({...obj1, ...obj2});

.as-console-wrapper { max-height: 100% !important; top: 0; }

连接两个对象而不分区数组

3 个答案: