我有一些测试,我需要一个使用Board.objects.create()
创建的Board对象,以使一个Object具有主键1
。但我已经想到,每个测试都有一个新对象,所以我在那里有例如'pk': 5
。如果我添加更多测试,'pk': 5
可能会出错,因为它会更改为'pk': 6
。对于所有测试,如何仅使用'pk': 1
创建一个Board对象?
我正在使用Django 2.0.3
from django.test import TestCase
from django.urls import reverse, resolve
from .views import home, board_topics, new_topic
from .models import Board
class BoardTopicsTests(TestCase):
def setUp(self):
Board.objects.create(name='Django', description='Django board.')
def test_board_topics_view_success_status_code(self):
url = reverse('boards:board_topics', kwargs={'pk': 5})
response = self.client.get(url)
self.assertEquals(response.status_code, 200)
def test_board_topics_view_not_found_status_code(self):
url = reverse('boards:board_topics', kwargs={'pk': 99})
response = self.client.get(url)
self.assertEquals(response.status_code, 404)
def test_board_topics_url_resolves_board_topics_view(self):
view = resolve('/boards/1/')
self.assertEquals(view.func, board_topics)
def test_board_topics_view_link_back_to_homepage(self):
board_topics_url = reverse('boards:board_topics', kwargs={'pk': 3})
response = self.client.get(board_topics_url)
homepage_url = reverse('boards:home')
self.assertContains(response, 'href="{0}"'.format(homepage_url))
def test_board_topics_view_contains_navigation_links(self):
board_topics_url = reverse('boards:board_topics', kwargs={'pk': 2})
homepage_url = reverse('boards:home')
new_topic_url = reverse('boards:new_topic', kwargs={'pk': 2})
response = self.client.get(board_topics_url)
self.assertContains(response, 'href="{0}"'.format(homepage_url))
self.assertContains(response, 'href="{0}"'.format(new_topic_url))
答案 0 :(得分:3)
您不应该依赖所创建对象的主键。在这种情况下,您可以将电路板存储为属性
def setUp(self):
self.board = Board.objects.create(name='Django', description='Django board.')
然后在测试中使用它的pk。
def test_board_topics_view_success_status_code(self):
url = reverse('boards:board_topics', kwargs={'pk': self.board.pk})
这将使您的测试套件更加强大。目前,如果运行测试的子集,或者以不同的顺序运行测试,则测试可能会失败。