Question

我在一个类中有一个定义，它以我不喜欢的方式处理异常。

类本身位于一个模块中，该模块本身由我导入的模块调用。

我不喜欢的错误处理看起来像这样：

class BitSharesWebsocket(Events):

    #[snip]

    def run_forever(self):
        """ This method is used to run the websocket app continuously.
            It will execute callbacks as defined and try to stay
            connected with the provided APIs
        """
        cnt = 0
        while not self.run_event.is_set():
            cnt += 1
            self.url = next(self.urls)
            log.debug("Trying to connect to node %s" % self.url)
            try:
                # websocket.enableTrace(True)
                self.ws = websocket.WebSocketApp(
                    self.url,
                    on_message=self.on_message,
                    on_error=self.on_error,
                    on_close=self.on_close,
                    on_open=self.on_open
                )
                self.ws.run_forever()
            except websocket.WebSocketException as exc:
                if (self.num_retries >= 0 and cnt > self.num_retries):
                    raise NumRetriesReached()

                sleeptime = (cnt - 1) * 2 if cnt < 10 else 10
                if sleeptime:
                    log.warning(
                        "Lost connection to node during wsconnect(): %s (%d/%d) "
                        % (self.url, cnt, self.num_retries) +
                        "Retrying in %d seconds" % sleeptime
                    )
                    time.sleep(sleeptime)

我希望在这里取代例外：

except websocket.WebSocketException as exc:

以我自己的方式处理它，即尝试新地址而不是一次又一次地尝试相同的地址。

我在调用时遇到此异常：

from bitshares.blockchain import Blockchain
from bitshares import BitShares

try:
    chain = Blockchain(bitshares_instance=BitShares(n))
except:
    print ('hello world')
    pass

当n是错误/无响应的websocket地址时

我从未收到'hello world'消息，因为模块在我之前处理异常。

该模块在github上托管：

https://github.com/xeroc/python-bitshares/blob/9250544ca8eadf66de31c7f38fc37294c11f9548/bitsharesapi/websocket.py

我能做到：

from bitsharesapi import websocket as ws

但我不知道如何处理模块现在它被导入以抢占其异常处理，或者这甚至是接近它的正确方法。

Answer 1

我在这里解决了我的问题：

chain = Blockchain(bitshares_instance=BitShares(n))

我能够做到：

chain = Blockchain(bitshares_instance=BitShares(n,num_retries=0))

我之前尝试过这个并假设它不起作用：

chain = Blockchain(bitshares_instance=BitShares(n),num_retries=0)

*注意括号放置

覆盖导入模块的类函数中的异常处理

1 个答案: