Question

嘿伙计我通常不使用正则表达式，所以我需要一些帮助来从下面的字符串中获取一些匹配。我只希望粗体信息与正则表达式匹配，任何帮助或解释都将不胜感激。

＆＃39;＆＃34; FM 2222 RD / RIVER PLACE BLVD＆＃34;，＆＃34; 0：＆＃34; ,,＆＃34; 18：＆＃34;，＆＃34; 00＆＃34;，＆＃34; 2008-08-14 ＆＃34;，＆＃34; CRASH /离开场景＆＃34;，＆＃34; 30.39452568＆＃34;＆＃34;（30.39452568-97.84551164）＆＃34;＆＃34; -97.84551164＆＃34;＆＃34; 18：00：00＆＃34;＆＃34; 4＆＃ 34;，＆＃34; 2008-08-14 18：00：00-06：00＆＃34;，＆＃34; 20085043619＆＃34;＆＃39;

Answer 1

如果您需要检测日期和旁边的字段，可以使用以下正则表达式：

expression = '"\d{4}-\d{2}-\d{2}","[^"]*"'

工作示例：

import re
my_str = '"FM 2222 RD / RIVER PLACE BLVD","0:",,"18:","00","2008-08-14","CRASH/LEAVING THE SCENE","30.39452568","(30.39452568-97.84551164)","-97.84551164","18:00:00","4","2008-08-14 18:00:00-06:00","20085043619"'
expression = '"\d{4}-\d{2}-\d{2}","[^"]*"'
re.findall(expression, my_str)  # returns ['"2008-08-14","CRASH/LEAVING THE SCENE"']

Answer 2

您提供的字符串看起来像csv文件中的一行，另一个选项是使用Pythons csv module。

由于我不知道你是否有一个充满这些字符串的文件或列表，这个例子展示了如何使用csv.reader将这个字符串读入io.StringIO（Python 3.6）。 4）

In[2]: s = '"FM 2222 RD / RIVER PLACE BLVD","0:",,"18:","00","2008-08-14","CRASH/LEAVING THE SCENE","30.39452568","(30.39452568-97.84551164)","-97.84551164","18:00:00","4","2008-08-14 18:00:00-06:00","20085043619"'
  ...: 
In[3]: import csv
  ...: import io
  ...: 
  ...: reader = csv.reader(io.StringIO(s))
  ...: for line in reader:
  ...:     address, a, b, c, d, date, msg, *stuff = line
  ...:     print(date)
  ...:     print(msg)
  ...: 
2008-08-14
CRASH/LEAVING THE SCENE

如果您的实际csv文件包含标题，则可以使用csv.DictReader然后执行print(line['date'])之类的操作（假设密钥为'date'）。

正则表达式字符串逗号，字符

2 个答案: