Question

我有这张桌子：

CREATE TABLE `count_traffic` (
  `tool_id` int(11) NOT NULL,
  `leads` int(11) NOT NULL DEFAULT '0',
  `date` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

关注SELECT：

$query="
SELECT sum(`leads`) as leads
     , date  
  FROM count_traffic 
 WHERE tool_id = :tool_id  
   AND date BETWEEN '2018-03-13' AND '2018-03-14' 
 GROUP 
    BY date";

如果我使用date作为日期字段，这个SELECT会显示出良好的效果！我如何才能从datetime字段类型中选择两个日期和GROUP BY DATE？

Answer 1

您使用DATE()函数并将date列包装在该函数调用中。

SELECT sum(`leads`) as leads
     , DATE(`date`)
  FROM count_traffic 
 WHERE tool_id = :tool_id  
   AND date BETWEEN '2018-03-13' AND '2018-03-14' 
 GROUP 
    BY DATE(`date`)

Answer 2

我找到了解决方案，这也是需要的人选择的选择：

SELECT sum(`leads`) as leads, DATE_FORMAT(date,'%y-%m-%d') as date 
FROM count_traffic 
WHERE 
        tool_id = :tool_id  
    AND 
        DATE_FORMAT(date,'%Y-%m-%d') BETWEEN '2018-03-13' AND '2018-03-14' 
 GROUP BY DATE_FORMAT(date,'%Y-%m-%d');

Answer 3

下面我附上了小提琴链接......你检查一下...... http://sqlfiddle.com/#!9/6b1ebb/6

如何从DATE选择DATETIME表和按日期分组

3 个答案: