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我想像这样打印数组 -
Arr= ["abcd","1223"," 10829380","pqrs"]
答案 0 :(得分:3)
您应该遵循命名模式,而不是使用Arr
,因为这通常是使用的
对于班级名称。
arr = ["abcd","1223"," 10829380","pqrs"]
whitespace_removed_arr = arr.map { |item| item.strip }
map
迭代字符串数组(arr
)并构建一个包含块返回值的新数组。
如果您愿意,可以使用较短的版本:
arr = ["abcd","1223"," 10829380","pqrs"]
whitespace_removed_arr = arr.map(&:strip)
请注意,提出strip!
和map
(iof strip
的原位版本)的解决方案很可能在strip!
之后无法正常工作或工作(奇怪的是) )当字符串未更改时返回nil
。
"".strip => ""
"".strip! => nil
"".strip => ""
" ".strip! => ""
如果您想使用条带的inplace变体并修改原始数组,则需要使用each
arr.each(&:strip!)
each
会丢弃该块的返回值,而strip!
会修改该字符串。
答案 1 :(得分:1)
您可以使用Array#map!或Array.map。 Array#map!
更改原始数组,Array#map
返回一个新数组,以便原始数组保持不变。 map
函数迭代数组并为数组中的每个元素执行给定的块。
arr = ["abcd", "1223", " 10829380", "pqrs"]
arr.map!{ |el| el.strip }
arr
# => ["abcd", "1223", "10829380", "pqrs"]
# or
arr = ["abcd", "1223", " 10829380", "pqrs"]
arr.map{ |el| el.strip }
# => ["abcd", "1223", "10829380", "pqrs"]
arr
# => ["abcd", "1223", " 10829380", "pqrs"]
Btw:ruby中的变量以小写字母或_(arr
)开头。