从App.js类中的一个屏幕导航到另一个屏幕非常容易。我所做的是做了三个类:App.js,SearchList.js和Detail.js。但我面临的问题是如何在searchList.js类中的任何视图上从searchList.js导航到Detail.js。我应该在searchList.js中再次使用StackNavigator还是在App.js中声明所有类?
App.js
import React from 'react';
import { Image,Button, View, Text ,StatusBar,StyleSheet,Platform,TouchableOpacity,ImageBackground,Picker,Alert,TouchableHighlight} from 'react-native';
import { StackNavigator,DrawerNavigator,DrawerItems } from 'react-navigation';
import {Constants} from "expo";
import SearchList from './classes/SearchList';
import Detail from './classes/Detail';
const DrawerContent = (props) => (
<View>
<View
style={{
backgroundColor: '#f50057',
height: 160,
alignItems: 'center',
justifyContent: 'center',
}}
>
<Text style={{ color: 'white', fontSize: 30 }}>
Header
</Text>
</View>
<DrawerItems {...props} />
</View>
)
class HomeScreen extends React.Component {
static navigationOptions = {
drawerLabel: 'Home',
drawerIcon: ({ tintColor }) => (
<Image
source={require('./images/crown.png')}
style={[styles.icon, {tintColor: '#f50057'}]}
/>
),
};
constructor(){
super();
this.state={PickerValueHolder : ''}
}
GetSelectedPickerItem=()=>{
Alert.alert(this.state.PickerValueHolder);
}
render() {
return (
<ImageBackground source={require('./images/green.png')} style={styles.backgroundImage} >
<TouchableOpacity onPress={() =>this.props.navigation.navigate('DrawerOpen')}>
<Image
source={require('./images/menu-button.png')}
style={styles.imagesStyle}
/>
</TouchableOpacity>
<View style={styles.columnContainer}>
<TouchableHighlight style={styles.search} underlayColor='#fff' onPress={() => this.props.navigation.navigate('SearchList')}>
<Text style={styles.searchText}>Search Hotels</Text>
</TouchableHighlight>
</View>
</ImageBackground >
);
}
}
class DetailsScreen extends React.Component {
render() {
return (
<View style={{ flex: 1, alignItems: 'center', justifyContent: 'center' }}>
<Text>Details Screen</Text>
<Button
title="Go to Details... again"
onPress={() => this.props.navigation.navigate('Details')}
/>
</View>
);
}
}
const styles = StyleSheet.create({
backgroundImage: {
flex: 1,
width: null,
height: null,
marginTop: Constants.statusBarHeight,
},
search:{
marginTop:20,
paddingTop:15,
borderRadius:8,
borderColor: '#fff'
},
searchText:{
color:'#fff',
textAlign:'center',
}
// backgroundColor: '#ef473a', // app color
});
const HomeStack = StackNavigator({
Home: {
screen: HomeScreen,
navigationOptions: ({ navigation }) => ({
header: null,
})
},
SearchList: { screen: SearchList },
Detail: { screen: Detail},
});
const RootStack = DrawerNavigator(
{
Home: {
screen: HomeStack,
},
DetailsScreen: {
screen: DetailsScreen,
},
},
{
initialRouteName: 'Home',
}
);
export default class App extends React.Component {
render() {
return <RootStack />;
}
}
SearchList.js
import React, { Component } from 'react';
import { StyleSheet, Platform, View, ActivityIndicator, FlatList, Text, Image, Alert, YellowBox,ImageBackground } from 'react-native';
import { StackNavigator,} from 'react-navigation';
import Detail from './classes/Detail';
export default class SearchList extends Component {
constructor(props) {
super(props);
this.state = {isLoading: true}
YellowBox.ignoreWarnings([
'Warning: componentWillMount is deprecated',
'Warning: componentWillReceiveProps is deprecated',
]);
}
GetItem (flower_name) {
Alert.alert(flower_name);
}
FlatListItemSeparator = () => {
return (
<View
style={{
height: .0,
width: "100%",
backgroundColor: "#000",
}}
/>
);
}
webCall=()=>{
return fetch('https://reactnativecode.000webhostapp.com/FlowersList.php')
.then((response) => response.json())
.then((responseJson) => {
this.setState({
isLoading: false,
dataSource: responseJson
}, function() {
// In this block you can do something with new state.
});
})
.catch((error) => {
console.error(error);
});
}
componentDidMount(){
this.webCall();
}
render() {
if (this.state.isLoading) {
return (
<View style={{flex: 1, justifyContent: 'center', alignItems: 'center'}}>
<ActivityIndicator size="large" />
</View>
);
}
return (
<View style={styles.MainContainer}>
<FlatList
data={ this.state.dataSource }
ItemSeparatorComponent = {this.FlatListItemSeparator}
renderItem={({item}) =>
<ImageBackground source= {{ uri: item.flower_image_url }} style={styles.imageView}
onPress={() => this.props.navigation.navigate('Detail')}>
</ImageBackground>
}
keyExtractor={(item, index) => index.toString()}
/>
</View>
);
}
}
const styles = StyleSheet.create({
MainContainer :{
justifyContent: 'center',
flex:1,
margin: 5,
marginTop: Constants.statusBarHeight , //(Platform.OS === 'ios') ? 20 : 14,
},
imageView: {
width: '100%',
height: 220 ,
margin: 7,
borderRadius : 40,
},
});
const HomeStack = StackNavigator({
Detail: { screen: Detail},
});
export default class App extends React.Component {
render() {
return <HomeStack />;
}
}
任何帮助都会很明显。
答案 0 :(得分:2)
要导航到您需要拥有导航对象的任何屏幕。可以通过两种方式提供导航对象
StackNavigator
如果您使用第一种方法,并且需要从SecondScreen
导航到ThirdScreen
,则应首先在StackNavigator
中声明两个屏幕,然后导航才会成功
如果您使用任何普通组件(例如模态框)导航到另一个屏幕,您需要做的就是将导航道具(this.props.navigation
)传递给模态框组件并使用道具导航到另一个屏幕。这里唯一的要求是this.props.navigation
应该在加载模态框组件的类中可用。
修改强>
根据要求,这是片段
const App = StackNavigator({
FirstScreen: { screen: FirstScreen},
SecondScreen: { screen: SecondScreen},
ThirdScreen: { screen: ThirdScreen}
})
export default App;
在SecondScreen
中,声明对象const { navigate } = this.props.navigation;
并点击一下按钮,使用此对象导航到另一个屏幕navigate("ThirdScreen");
关于第二种方法,如果您的组件是模态,则可以将navigate
对象作为 - <Modal navigation={navigate} />
传递,并在模态组件中将其用作this.props.navigation("ThirdScreen");
希望现在澄清一下。
答案 1 :(得分:0)
支持我们将js
命名为SecondScreen.js
与App.js
位于同一目录级别,然后我们应该在App.js
import SecondScreen from './SecondScreen';
它对我有用。希望这对你也有帮助。
答案 2 :(得分:0)
我认为您正在尝试实现堆栈导航器的功能。 转到React-Navigation-Docs。在堆栈导航器中,您可以制作一叠屏幕,并从一个屏幕导航到另一个屏幕。在index.js里面:
import { StackNavigator, TabNavigator } from "react-navigation";
import SplashScreen from "./src/screens/start/splash";
import LoginScreen from "./src/screens/start/login";
import DomainScreen from "./src/screens/start/domain";
const App = StackNavigator(
{
Splash: {
screen: SplashScreen,
},
Domain: {
screen: DomainScreen,
},
Login: {
screen: LoginScreen,
},
Tabs: {
screen: HomeTabs,
}
},
{
initialRouteName: "Splash",
}
);
AppRegistry.registerComponent("app_name", () => App);
然后您可以使用this.props.navigation.navigate("ScreenName")