Question

如何在int和float中为python3获取用户的输入？

显然编写了一个计算器，但我希望用户的输入在int和float中，不仅仅是int或float，而且两者都是。这基本上都是我所关心的，将int更改为get int和float。可悲的是，Java使用了双倍。

def calculator():
    def add(x, y):
        return x + y

    def sub(x, y):
        return x - y

    def mul(x, y):
        return x * y

    def div(x, y):
        return x / y

    def power(x, y):
        return x ** y

    def modulus(x, y):
        return x % y

    print(""" -- Select Operation --
    1. Addition
    2. Subtraction
    3. Multiplication
    4. Division
    5. Power
    6. Modulus
    """)

    choice = input("Enter 1 or 2 or 3 or 4 or 5 or 6 from the Select Operation >> ")
    while choice not in ('1', '2', '3', '4', '5', '6'):
        choice = input("Invalid Input! Please Enter 1 or 2 or 3 or 4 or 5 or 6 from the Select Operation >> ")
    print("\n")
    print("============================================================")
    print("Gathering data...")
    # How to make user input in both int and float not int alone?
    num1 = int(input("Enter First number >> "))
    num2 = int(input("Enter Second number >> "))

    if choice == '1':
        print(num1, "+", num2, "=", add(num1, num2))
    elif choice == '2':
        print(num1, "-", num2, "=", sub(num1, num2))
    elif choice == '3':
        print(num1, "*", num2, "=", mul(num1, num2))
    elif choice == '4':
        print(num1, "/", num2, "=", div(num1, num2))
    elif choice == '5':
        print(num1, "^", num2, "=", power(num1, num2))
    elif choice == '6':
        print(num1, "%", num2, "=", modulus(num1, num2))
    repeat_cal()

def repeat_cal():
    print("Do you want to Select Operation again")
    choose_again = input("Enter Y for YES or N for NO>> ")
    if choose_again.upper() == 'Y':
        calculator()
    elif choose_again.upper() == 'N':
        print("-----------------Good Bye!---------------------------")
        exit()
    else:
        repeat_cal()

calculator()

Answer 1

我建议你把输入作为浮点数。这样，如果用户输入浮动，您可以支持它。

如果用户输入了一个int，它也会受到支持。如果由于某种原因，您想要检查输入是否为int，则可以检查该数字在小数点后是否为0。

Answer 2

使用字符串构造函数将输入作为decimal.Decimal，以避免浮点精度损失。十进制可以表示包括整数在内的任意精度，并且总是返回计算器所期望的值。

def calculator():
    def add(x, y):
        return x + y

    def sub(x, y):
        return x - y

    def mul(x, y):
        return x * y

    def div(x, y):
        return x / y

    def power(x, y):
        return x ** y

    def modulus(x, y):
        return x % y

    print(""" -- Select Operation --
    1. Addition
    2. Subtraction
    3. Multiplication
    4. Division
    5. Power
    6. Modulus
    """)
    from decimal import Decimal
    choice = input("Enter 1 or 2 or 3 or 4 or 5 or 6 from the Select Operation >> ")
    while choice not in ('1', '2', '3', '4', '5', '6'):
        choice = input("Invalid Input! Please Enter 1 or 2 or 3 or 4 or 5 or 6 from the Select Operation >> ")
    print("\n")
    print("============================================================")
    print("Gathering data...")
    # How to make user input in both int and float not int alone?
    num1 = Decimal(input("Enter First number >> "))
    num2 = Decimal(input("Enter Second number >> "))

    if choice == '1':
        print(num1, "+", num2, "=", str(add(num1, num2)))
    elif choice == '2':
        print(num1, "-", num2, "=", str(sub(num1, num2)))
    elif choice == '3':
        print(num1, "*", num2, "=", str(mul(num1, num2)))
    elif choice == '4':
        print(num1, "/", num2, "=", str(div(num1, num2)))
    elif choice == '5':
        print(num1, "^", num2, "=", str(power(num1, num2)))
    elif choice == '6':
        print(num1, "%", num2, "=", str(modulus(num1, num2)))
    repeat_cal()

def repeat_cal():
    print("Do you want to Select Operation again")
    choose_again = input("Enter Y for YES or N for NO>> ")
    if choose_again.upper() == 'Y':
        calculator()
    elif choose_again.upper() == 'N':
        print("-----------------Good Bye!---------------------------")
        exit()
    else:
        repeat_cal()

calculator()

如何在int和float中为python3

2 个答案: