Question

我是新的PHP！。

我有一个包含日期和值的数组。我如何获得所有的价值观具体日期？ EXP：我想从2015年获得所有价值。如果有人知道可以指导我。

Answer 1

您可以使用array_filter，然后检查数组键substr是否与日期匹配。

<?php
$date = 2016;

$array = [
    '2016-01-01' => 'a',    
    '2016-01-02' => 'b',    
    '2016-12-01' => 'c',    
    '2017-01-04' => 'd',    
    '2017-01-05' => 'e',    
    '2017-01-06' => 'f',    
];

$result = array_filter($array, function ($key) use ($date) {
    return substr($key, 0, strlen($date)) == $date;
}, ARRAY_FILTER_USE_KEY);

print_r($result);

https://3v4l.org/UYaQq

<强>结果：

Array
(
    [2016-01-01] => a
    [2016-01-02] => b
    [2016-12-01] => c
)

Answer 2

<?php
$array = array('2015-01-01' => "test1",
                '2013-02-04' => "test2",
                '2011-03-08' => "test3",
                '2016-03-08' => "test3");

foreach( $array as $key => $value ){
    if(date('Y',strtotime($key)) >= 2015)
        echo $value . ", ";
}

?>

Answer 3

An Array Contains a Key and a Value. The Key in your case is the Date. And the Value is... the value

You define it like this

$array = array(
    Date => Value,
    AnotherDate => AnotherValue,
);

or since PHP5

$array = [
      Date => Value,
      AnotherDate => AnotherValue,
];

if you now look at your Array using

var_dump($array);

You'll see the date is already combined with your value and It will even show the type of value (boolean, string, integer...)

Edit Anotherone was faster

PHP：按日期获取值

3 个答案: