Question

该程序与

的预期功能一起使用

使用用户输入创建列表以生成五个名称
使用用户输入创建一个列表，以数字形式生成五个标记/等级。
创建第三个列表，组合中的每个元素第一个列表，第二个列表中有相应的索引位置。

例如：

Student_Names= []
Marks= []
StudentNames_Marks= []
for i in range (5): #Go through and append the student names into Student_Names list by requesting the information five times and appending each time
    _name= input("Please enter a name for the student records list. ")
    Student_Names.append(_name)
_sum=0 #This is used to create a second for loop under the event that they do not enter a digit within the first list, allowing them to continue forward
for i in range (5):
    _marks= input("Please enter marks in digit format. ")
    if _marks.isalpha():
        print("Please enter a digit, such as 10 instead of ten.")
        _sum=_sum+1 #Add one to the sum to create the amount of loops in the second for loop
    else:
        Marks.append(_marks)
if _sum>0:
    for i in range(_sum):
        _marks=input("Please enter marks in digit format. ")
        if _marks.isalpha():
            print("Please enter a digit, such as 10 instead of ten. The program will not run properly. Please restart the program.")
        else:
            Marks.append(_marks)
_numbera= len(Student_Names) #Using the lengths of the list to determine the length of the for loop
_numberb= len(Marks)
_length= _numbera+_numberb
for i in range (5):
    _value=Student_Names.pop()
    StudentNames_Marks.append(_value)
    _value=Marks.pop()
    StudentNames_Marks.append(_value)

print(StudentNames_Marks)

如果在提示符中输入以下内容，则会在控制台上生成以下内容：

姓名提示回复：James，Jack，Ivy，Eva，Lee Marks：10,64,36， 86,35 Student_Names = ['James'，'Jack'，'Ivy'，'Eva'，'Lee'] Marks = ['10'，'64'，'36'，'86'，'35'] StudentNames_Marks = ['Lee'，'35'， '伊娃'，'86'，'常春藤'，'36'，'杰克'，'64'，'詹姆斯'，'10'

然而，我坚持开发最后一步。我已经获得了一个列表，该列表以正确的顺序从前两个列表中获取元素，如上所示。我不确定如何将最终列表中的元素组合成一个破折号，所以看起来更像是这样：

StudentNames_Marks = ['Lee-35'，'Eva-86'，'Ivy-36'，'Jack-64'， '詹姆斯10']

我该怎么做呢？

Answer 1

使用zip和list comprehension的一个班轮：

>>> ['-'.join(ele) for ele in zip(student_names, marks)]

此处，zip命令用于创建组合student_name和marks的元组，然后使用join函数将它们连接在一起。

#driver values：

IN : student_names= ['James', 'Jack', 'Ivy', 'Eva', 'Lee']
IN : marks = ['10', '64', '36', '86', '35']
OUT : ['James-10', 'Jack-64', 'Ivy-36', 'Eva-86', 'Lee-35']

Answer 2

替代方式（仅使用一个列表）：

您可以使用zip一次从一个列表中获取两个项目，并在它们之间添加-。

StudentNames_Marks= ['Lee', '35', 'Eva', '86', 'Ivy', '36', 'Jack', '64', 'James', '10']

def group(iterable, n):
   return zip(*[iter(iterable)]*n)

StudentNames_Marks_new = []
for x, y in group(StudentNames_Marks, 2):
    StudentNames_Marks_new.append('{}-{}'.format(x, y))

print(StudentNames_Marks_new)

# ['Lee-35', 'Eva-86', 'Ivy-36', 'Jack-64', 'James-10']

Answer 3

student_names= ['James', 'Jack', 'Ivy', 'Eva', 'Lee']
marks = ['10', '64', '36', '86', '35']

result = ["{}-{}".format(name, mark) for name, mark in zip(student_names, marks)]

Answer 4

要将最终输出转换为所需的输出，您可以使用：

StudentNames_Marks = ['Lee', '35', 'Eva', '86', 'Ivy', '36', 'Jack', '64', 'James', '10']
StudentNames_Marks = ['-'.join(nm) for nm in zip(StudentNames_Marks[::2],StudentNames_Marks[1::2]]
StudentNames_Marks
#['Lee- 35', 'Eva- 86', 'Ivy- 36', 'Jack- 64', 'James- 10']

Answer 5

你可以使用理解力：

# combine every name with the corresponding mark
def combine(names, marks):
    if len(names) != len(marks):
        # throw an exception or return some error value
        pass
    else:
        return [name + '-' + mark for name, mark in zip(names, marks)]

用短划线将两个单独列表中的单独元素组合在一起

5 个答案: