最近我正在研究将视频上传到服务器的代码。发布到php时它可以正常工作。
PHP代码适用于android：
<?php
$file_path = $_SERVER['DOCUMENT_ROOT'].'/uploads/'; //$_SERVER['DOCUMENT_ROOT'] is neccessary and slash before 'uploads'
$file_path = $file_path . basename( $_FILES['uploaded_file']['name']);
if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $file_path)) {
echo "success".$file_path;
} else{
echo "fail";
}
?>
ASP .Net代码将Not Found ServerResponse返回给android
[HttpPost]
public HttpResponseMessage UploadFile(HttpPostedFileBase file)
{
try
{
if (file.ContentLength > 0)
{
string _FileName = Path.GetFileName(file.FileName);
string _path = Path.Combine(System.Web.HttpContext.Current.Server.MapPath("~/Videos"), _FileName);
file.SaveAs(_path);
}
return Request.CreateResponse(HttpStatusCode.OK, "success");
}
catch
{
return Request.CreateResponse(HttpStatusCode.BadRequest, "failed");
}
}
用于上传视频的Android代码
private int uploadVideo(String sourceFileUri) {
String fileName = sourceFileUri;
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(sourceFileUri);
if (!sourceFile.isFile()) {
dialog.dismiss();
Log.e("uploadFile", "Source File not exist :" + selectedVideoPath);
runOnUiThread(new Runnable() {
public void run() {
videoURL.setText("Source File not exist :" + selectedVideoPath);
}
});
return 0;
} else {
try {
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL("http://domain.online/api/User/FileUpload");
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\"" + fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
final String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : " + serverResponseMessage + ": " + serverResponseCode);
if (serverResponseCode == 200) {
runOnUiThread(new Runnable() {
public void run() {
String msg = "File Upload Completed.\n\n See uploaded file here : \n\n" + serverResponseMessage;
videoURL.setText(msg);
Toast.makeText(PostNewTarget.this, "File Upload Complete.", Toast.LENGTH_SHORT).show();
}
});
} else {
runOnUiThread(new Runnable() {
public void run() {
String msg = "File Upload Completed.\n\n See uploaded file here : \n\n" + serverResponseMessage;
videoURL.setText(msg);
Toast.makeText(PostNewTarget.this, "File Upload Complete.", Toast.LENGTH_SHORT).show();
}
});
}
// close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
dialog.dismiss();
ex.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(PostNewTarget.this, "MalformedURLException", Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
dialog.dismiss();
e.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(PostNewTarget.this, "Got Exception : see logcat ", Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload f - s Exception", "Exception : " + e.getMessage(), e);
}
dialog.dismiss();
return serverResponseCode;
}
}
有没有更好的方法在.Net上接收视频文件？ 这与IIS有关吗？ 我在这里错过了什么
答案 0 :(得分：0)
解决了这个问题。实际上我们必须在ASP .NET中接收视频文件作为MultipartFileData 以下是ASP .Net代码。 CustomMultipartFormDataStreamProvider类有助于保存视频文件名。
public class UploadController : ApiController
{
[HttpPost]
public async Task<HttpResponseMessage> PostUpload()
{
// Check whether the POST operation is MultiPart?
if (!Request.Content.IsMimeMultipartContent())
{
throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
}
// Prepare CustomMultipartFormDataStreamProvider in which our multipart form
// data will be loaded.
string fileSaveLocation = HttpContext.Current.Server.MapPath("~/App_Data");
CustomMultipartFormDataStreamProvider provider = new CustomMultipartFormDataStreamProvider(fileSaveLocation);
List<string> files = new List<string>();
try
{
// Read all contents of multipart message into CustomMultipartFormDataStreamProvider.
await Request.Content.ReadAsMultipartAsync(provider);
foreach (MultipartFileData file in provider.FileData)
{
files.Add(Path.GetFileName(file.LocalFileName));
}
// Send OK Response along with saved file names to the client.
return Request.CreateResponse(HttpStatusCode.OK, files);
}
catch (System.Exception e)
{
return Request.CreateErrorResponse(HttpStatusCode.InternalServerError, e);
}
}
}
// We implement MultipartFormDataStreamProvider to override the filename of File which
// will be stored on server, or else the default name will be of the format like Body-
// Part_{GUID}. In the following implementation we simply get the FileName from
// ContentDisposition Header of the Request Body.
public class CustomMultipartFormDataStreamProvider : MultipartFormDataStreamProvider {
public CustomMultipartFormDataStreamProvider(string path) : base(path) { }
public override string GetLocalFileName(System.Net.Http.Headers.HttpContentHeaders headers) {
return headers.ContentDisposition.FileName.Replace("\"", string.Empty);
}
}