Question

这里我有2个微调器。单击button1时，将执行以下过程。该过程是关于获取微调器值，并且这些值必须存储在总变量中，并且必须将选定的微调器值重置为原始位置。此操作应执行单击按钮的次数。

Spinner cre1，cre2;

浮动总数;

String credit1，credit2;

ArrayAdapter spin1;

ArrayAdapter spin2;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_example);

    creditd = new ArrayAdapter<String>(this, android.R.layout.simple_spinner_item, spin1);
    graded = new ArrayAdapter<String>(this, android.R.layout.simple_spinner_item, spin2);

    cre1 = (Spinner) findViewById(R.id.cre1);
    spin1.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    cre1.setAdapter(creditd);
    cre1.setOnItemSelectedListener(new OnItemSelectedListener() {
        @Override
        public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {
            credit1 = adapterView.getItemAtPosition(i).toString();
        }

        @Override
        public void onNothingSelected(AdapterView<?> adapterView) {

        }
    });

    cre2 = (Spinner) findViewById(R.id.cre2);
    spin2.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    gra1.setAdapter(graded);
    gra1.setOnItemSelectedListener(new OnItemSelectedListener() {
        @Override
        public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {
            credit2 = adapterView.getItemAtPosition(i).toString();
        }

        @Override
        public void onNothingSelected(AdapterView<?> adapterView) {

        }
    });


    total += convf(credit1) + convf(credit2);
}

@Override
public void onClick(View view) {
    switch (view.getId()) {
        case R.id.button1:
            onCreate(new Bundle());
            break;

        case R.id.button2:
            startActivity(new Intent(this, Result.class));
            break;
    }
}

@Override
public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {

}

@Override
public void onNothingSelected(AdapterView<?> adapterView) {

}

Answer 1

您可以使用Spinners setSelection方法重置所选位置，如您所愿：

spin1.setSelection(position); 
spin2.setSelection(position);

获取，重置Spinner值并显式调用onCreate方法

1 个答案: