我想用一个带有AJAX响应函数的select2下拉列表填充数据,只要它所需的下拉列值改变值就会被调用。我控制台登录以确保达到该功能,但是,机器没有运行说明:
create.tpl - 保留前端代码
$('.select2lead').select2({
minimumInputLength: 3,
ajax: {
type: 'GET',
url: '/modules/support/ajaxLeadSearch.php',
dataType: 'json',
delay: 250,
data: function (params) {
return {
term: params.term
};
},
processResults: function (data) {
return {
results: data,
more: false
};
}
}
});
$('.select2lead').on("change", function() {
var value = $(this).val();
// console.log(value);
searchProjectsByLeadID(value);
});
function searchProjectsByLeadID(id){
$('.select2project').select2({
minimumInputLength: 3,
ajax: {
type: 'GET',
url: '/modules/support/ajaxProjectSearch.php',
dataType: 'json',
delay: 250,
data: {
"id": id
},
processResults: function (data) {
return {
results: data,
more: false
};
}
}
});
console.log(id);
}
ajaxProjectSearch.php
<?php
require_once('../../config.php');
$login = new Login();
if (!$login->checkLogin()) {
echo lang($_SESSION['language'], "INSUFFICIENT_RIGHTS");
exit();
}
$db = new Database();
// Select the projects
$query = "
SELECT
ProjectID AS project_id,
ProjectSummaryShort AS project_summary,
FROM
`rapports_projectTBL`
INNER JOIN LeadTBL ON rapports_projectTBL.LeadID=LeadTBL.LeadID
WHERE
ProjectID > 0
AND
rapports_projectTBL.LeadID LIKE :leadId
ORDER BY
ProjectID
ASC
";
$binds = array(':leadId' => $_GET['id']);
$result = $db->select($query, $binds);
$json = [];
foreach ($result as $row){
$json[] = ['id'=>$row['project_id'], 'text'=>$row['project_summary']];
}
echo json_encode($json);
控制台中的网络输出
https://i.imgur.com/6ZmGGxa.png *正如我们所看到的,searchProjectsByLeadID(id)函数被调用,但我们什么也得不到。没有错误也没有任何价值。传输的唯一方法是第一个选择框,它在搜索框中键入的内容中获取潜在客户数据。 *
答案 0 :(得分:0)
<强>分辨强>
通过让SQL查询查找LIKE而不是DIRECT MATCH来调用问题:
WRONG
哪里
ProjectID&gt; 0
和
rapports_projectTBL.LeadID LIKE:leadId
CORRECT
哪里
rapports_ProjectTBL.LeadID =:leadId