Question

cur = conn.cursor()

result = cur.execute("SELECT * FROM users WHERE username = %s", [username])
if result > 0:
    data = cur.fetchone()
    password = data['password']

if sha256_crypt.verify(password_given, password):
    app.logger.info('PASSWORD MATCHED')
else:
    app.logger.info('PASSWORD Not MATCHED')

这是我正在使用的实际代码。我认为错误来自变量'result'，我希望它将存储的密码作为字典。

Answer 1

cur.execute()没有返回结果：您必须使用cur.fetchone()获得结果。如果没有找到结果，它将返回None，否则它将根据使用的游标类返回元组或dict：

cur = conn.cursor()

cur.execute("SELECT * FROM users WHERE username = %s", [username])
data = cur.fetchone()
if data:
    password = data['password']

Answer 2

将单引号放在%s左右，因为username是一个字符串

result = cur.execute("SELECT * FROM users WHERE username = '%s'"%str(username))

if result.rowcount >0

Corretion

cur = conn.cursor()

result = cur.execute("SELECT * FROM users WHERE username = %s", [username])
data = cur.fetchone()
if result.rowcount > 0:
    password = data['password']


    if sha256_crypt.verify(password_given, password):
        app.logger.info('PASSWORD MATCHED')
    else:
        app.logger.info('PASSWORD Not MATCHED')

TypeError：unorderable类型：NoneType（）＆gt;从postgres数据库中检索int（）

2 个答案: