我的任务是利用循环。该计划应接受3名员工（玛丽，汤姆和克里斯）的销售投入。流程应如下：
初始？ ＆GT;要输入的销售数量＆gt;输入销售额＆gt;显示17％的佣金>将佣金和销售额添加到相应的变量＆gt;＆gt;继续直到＆＃39; z＆＃39;输入为inputSalesPerson＆gt;＆gt;显示信息
所以我试图弄清楚为什么我的tempComm变量的返回值没有返回正确的值。如果我要进入＆＃39;对于变量inputSalesPerson，它让我进入开关盒＆＃39; t＆＃39;没问题。输入销售数量和工作量。但是当我进入salesAmount然后显示佣金时，它将无法正确计算。
如果我输入＆＃39; z＆＃39;或者＆＃39; Z＆＃39;作为inputSalesPerson，它不会结束程序。我有很多事要做。
#include <iomanip>
#include <iostream>
using namespace std;
int main()
{
int salesT = 0, salesC = 0, salesM = 0;
double amountT = 0, amountC = 0, amountM = 0;
double commT = 0, commC = 0, commM = 0;
double commRate = (17/100);
int num_sales;
double salesAmount, totalSales, tempComm;
char inputSalesPerson;
do
{
cout << "Enter the sales person's initial (\"Z\" to quit): ";
cin >> inputSalesPerson;
while(inputSalesPerson != 't' && inputSalesPerson != 'T' && inputSalesPerson != 'm' && inputSalesPerson != 'M' && inputSalesPerson != 'c' && inputSalesPerson != 'C' && inputSalesPerson != 'z' && inputSalesPerson != 'Z')
{
cin.get();
system("cls");
cout << "Invalid input for employee. Please Input (T)om, (C)hris, (M)ary, or (Z) to End : ";
cin >> inputSalesPerson;
}
switch(inputSalesPerson)
{
case 't' :
case 'T' :
system("cls");
cout << "Enter the number of sales : ";
cin >> num_sales;
while(num_sales < 1 || num_sales > 5)
{
system("cls");
cout << "Invalid number of sales. Please enter a value between 1 and 5 : ";
cin >> num_sales;
}
salesT += num_sales;
for(int i = 0; i<num_sales; i++)
{
cin.get();
system("cls");
cout << "Enter the sale amount : ";
cin >> salesAmount;
while(salesAmount < 0)
{
cin.get();
system("cls");
cout << "Invalid sale amount. Please enter a positive amount : ";
cin >> salesAmount;
}
tempComm = salesAmount + (salesAmount * commRate);
cout << fixed << setprecision(2) << "Commission earned by tom on this sale is : " << tempComm << endl;
cin.get();
amountT += salesAmount + tempComm;
commT += tempComm;
totalSales += amountT;
}
break;
}
}while(inputSalesPerson != 'z' || 'Z');
return 0;
}
**** **** EDIT 感谢您提供有关单步调试的信息。感谢这个评论，我能够更深入地学习如何使用调试工具，这有助于我让一切工作更好。
答案 0 :(得分：0)
我在需要修复的区域评论了您的代码。此外，在整个地方使用cin.get（）存在问题。我假设您这样做是为了在每次输入后丢弃返回字符。但是如果在调用cin.get（）时标准输入（cin）为空，它将阻止程序直到输入内容。当您输入多个num_sales时会发生这种情况：
for (int i = 0; i<num_sales; i++)
{
cin.get();
它处理第一个罚款，但在第二个循环中你得到：
Enter the sale amount : 20
Commission earned by tom on this sale is : 23.40
// cin.get() blocks here, with no user instructions to enter the next sale amount
我已经注释掉了所有的cin.get（）。它仍然会起作用，因为cin运算符＆gt;＆gt;丢弃空格和换行符，所以即使缓冲区中仍然有\ n换行符，下次你执行类似cin＆gt;＆gt;的操作时num_sales它会丢弃换行符。
#include <iomanip>
#include <iostream>
using namespace std;
int main()
{
int salesT = 0, salesC = 0, salesM = 0;
double amountT = 0, amountC = 0, amountM = 0;
double commT = 0, commC = 0, commM = 0;
double commRate = (17 / 100.0); // Int divided by int will round to an int.
// commRate is 0.0. Divide by double instead (17 / 100.0)
int num_sales;
double salesAmount, totalSales = 0, tempComm; // totalSales needs to be initialised to
// zero, otherwise it holds a garbage value.
char inputSalesPerson;
do
{
cout << "Enter the sales person's initial (\"Z\" to quit): ";
cin >> inputSalesPerson;
while (inputSalesPerson != 't' && inputSalesPerson != 'T' && inputSalesPerson != 'm' && inputSalesPerson != 'M' && inputSalesPerson != 'c' && inputSalesPerson != 'C' && inputSalesPerson != 'z' && inputSalesPerson != 'Z')
{
//cin.get();
system("cls");
cout << "Invalid input for employee. Please Input (T)om, (C)hris, (M)ary, or (Z) to End : ";
cin >> inputSalesPerson;
}
switch (inputSalesPerson)
{
case 't':
case 'T':
system("cls");
cout << "Enter the number of sales : ";
cin >> num_sales;
while (num_sales < 1 || num_sales > 5)
{
system("cls");
cout << "Invalid number of sales. Please enter a value between 1 and 5 : ";
cin >> num_sales;
}
salesT += num_sales;
for (int i = 0; i<num_sales; i++)
{
//cin.get();
//system("cls");
cout << "Enter the amount for sale number " << i+1 << ": ";
cin >> salesAmount;
system("cls"); // I would put the clear here,
// Otherwise the user can't see the commission made by Tom
while (salesAmount < 0)
{
//cin.get();
system("cls");
cout << "Invalid sale amount. Please enter a positive amount : ";
cin >> salesAmount;
}
tempComm = salesAmount + (salesAmount * commRate);
cout << fixed << setprecision(2) << "Commission earned by tom on this sale is : " << tempComm << endl;
//cin.get();
amountT += salesAmount + tempComm;
commT += tempComm;
totalSales += amountT; // I think you mean to add salesAmount maybe?
}
break;
}
} //while (inputSalesPerson != 'z' || 'Z');
// Even if { this ^^^^} is false, ^^^ this is always
// 'Z' char will convert to bool, any non-zero value is true.
while (inputSalesPerson != 'z' && inputSalesPerson != 'Z');
return 0;
}