我正在使用Hibernate 4.2.6和Java DB
这是我的作品
RegisterationHelper.java
org.hibernate.Transaction tx = session.beginTransaction();
String uid = std.getUserid();
System.out.println(uid);
Query query = session.createQuery("FROM university.Student");
List<Student> student = query.list();
for(Iterator it= student.iterator(); it.hasNext();)
{
//some code....
{
try
{
tx = session.beginTransaction();
int rgstnum=0;
Query q = session.createQuery("Select max(registrationnumber)from Student");
List currentRegNo = q.list();
rgstnum=(Integer)currentRegNo.get(0)+1;
std.setRegistrationnumber(rgstnum);
sc.setRegistrationnumber(rgstnum);
Serializable objID=session.save(std);
session.saveOrUpdate(sc);
tx.commit();
}
catch(Exception e)
{
}
//priniting sc.getRegistrationnumber() showing null
//priniting sc.getCurseid() has data
和RegistrationForm.java
@ManagedBean
@RequestScoped
public class RegistrationForm {
public String submitAction() {
RegistrationHelper rghp = new RegistrationHelper();
Student std = new Student();
std.setFirstname(getFirstName().toString());
std.setLastname(getLastName().toString());
std.setGender(getGender().toString());
std.setDob(getDateofBirth());
std.setAddress(getAddress().toString());
std.setPhone(getContactNumber().toString());
std.setEmail(getEmailID().toString());
std.setUserid(getUserID().toString());
std.setPassword(getPassword().toString());
Studentcourse sc = new Studentcourse();
sc.setCourseid(getCourse().toString());
String msg = rghp.insertStudent(std, sc);
if(msg.equals("error"))
{
setUserIdError("User Id already exist");
setUserID("");
return "Registration";
}
else
{
return "Success";
}
}`
所以我认为只有查询Query q = session.createQuery("Select max(registrationnumber)from Student");
没有检索registrationumber
的问题,因为如果删除有关的代码,我可以将数据存储在Student
表中StudentCourse
和其他事情在服务器日志中获得Info: nested transactions not supported
所以,如果我的查询错误或其他原因,请。
答案 0 :(得分:1)
我不认为查询中存在问题:消息nested transactions not supported
指的是您打开事务(session.beginTransaction()
)两次,一次开始然后再一次打开。尝试删除第二个。