以下是带脚本的页面链接。 http://signsourceak.com/index1.html
这是我的脚本,由于某些原因,鼠标悬停时所有功能都会触发。任何人都可以告诉我我的剧本有什么问题
window.onload = sliding;
var tags = new Array('tag1','tag2','tag3','tag4','tag5','tag6','tag7','tag8');// List of headings
var pics = new Array('popout1','popout2','popout3','popout4','popout5','popout6','popout7','popout8');// list of images that slide out
function sliding(){ // assing event
for(var i=0; i< tags.length; i++){
document.getElementById(tags[i]).onmouseover = slideout(tags[i],pics[i]); // <-- The Problem is Here Function runs with out the actual event
document.getElementById(tags[i]).onmouseout = slidein(tags[i],pics[i]);
//alert('this worked,'+ tags[i] + pics[i]);
}
}
function slideout(hid,picid){
document.images[picid].style.visibility = "visible";
document.images[picid].style.MozOpacity = 0.7;// need browser compatability
moveout(hid,picid);
}
function moveout(hid,picid){
if(currpos(picid) > 0){
document.images[picid].style.top = currpos(picid) - 1 + "px";
setTimeout(moveout,10);
}else{
clearTimeout(moveout);
}
function currpos(element){
return document.getElementById(element).offsetTop;
}
}
function slidein(hid,picid){
document.images[picid].style.MozOpacity = 0.5;// need browser compatability
movein(hid,picid);
}
function movein(hid,picid){
if(currpos(picid) < 210){
document.images[picid].style.top = currpos(picid) + 1 + "px";
setTimeout(movein,10);
}else{
clearTimeout(movein);
document.images[picid].style.visibility = "hidden";
}
function currpos(element){
return document.getElementById(element).offsetTop;
}
}
答案 0 :(得分:1)
这不是如何使用clearTimeOut。
setTimeout返回必须传递给clearTimeOut的计时器ID:
var timer = setTimeout( fn, 10 );
clearTimeout( timer);
答案 1 :(得分:0)
您正在将slideout()和slidein()的结果指定为处理程序。您还需要隔离闭包变量;自调用函数将确保所有事件处理程序不共享i循环变量
function sliding(){ // assing event
for(var i=0; i< tags.length; i++){
document.getElementById(tags[i]).onmouseover =(function(index){
return function() {
slideout(tags[index],pics[index]);
}
})(i);
document.getElementById(tags[i]).onmouseout = (function(index){
return function() {
slidein(tags[index],pics[index]);
}
})(i);
}
}
答案 2 :(得分:0)
这里有一个问题:
function sliding(){ // assing event
for(var i=0; i< tags.length; i++){
document.getElementById(tags[i]).onmouseover = slideout(tags[i],pics[i]); // <-- The Problem is Here Function runs with out the actual event
document.getElementById(tags[i]).onmouseout = slidein(tags[i],pics[i]);
//alert('this worked,'+ tags[i] + pics[i]);
}
}
在那个循环中,你调用“slideout”和“slidein”函数,虽然很明显这不是你想要做的。您想要的目的是分配一个以适当的方式调用“slideout”或“slidein”的函数。要做到这一点,你需要另一层功能:
function makeHandlers(index) {
return {
'out': function() { slideout(tags[index], pics[index]; },
'in': function() { slidein(tags[index], pics[index]; }
};
}
function sliding() {
for (var i = 0; i < tags.length; ++i) {
var handlers = makeHandlers(i), tag = document.getElementById(tags[i]);
tag.onmouseover = handlers.in;
tag.onmouseout = handlers.out;
}
}
正如@BiAiB所说,你对“setTimeout”和“clearTimeout”的调用也需要引起注意。