Question

我尝试将聚合函数列添加到现有结果集中。我尝试过OVER（），UNION的变种，但无法找到解决方案。

示例当前结果集：

ID     ATTR     VALUE
1      score     5
1      score     7
1      score     9

示例所需结果集：

ID     ATTR     VALUE   STDDEV (score)
1      score     5       2
1      score     7       2
1      score     9       2

谢谢

Answer 1

看起来像你之后：

stddev(value) over (partition by attr)
stddev(value) over (partition by id, attr)

它只取决于你需要分区的内容。基于样本数据，attr应该足够;但我可以看到ID和attr。

示例：

With CTE (ID, Attr, Value) as (
SELECT 1, 'score', 5 from dual union all
SELECT 1, 'score', 7 from dual union all
SELECT 1, 'score', 9 from dual union all 
SELECT 1, 'Z', 1 from dual union all
SELECT 1, 'Z', 5 from dual union all
SELECT 1, 'Z', 8 from dual)

SELECT A.*, stddev(value) over (partition by attr)  
FROM cte A
ORDER BY attr, value

DOCS表明通过向分析添加订单，可以获得每条记录的累积标准差。

给我们：

+----+-------+-------+------------------------------------------+
| ID | attr  | value |                  stdev                   |
+----+-------+-------+------------------------------------------+
|  1 | Z     |     1 | 3.51188458428424628280046822063322249225 |
|  1 | Z     |     5 | 3.51188458428424628280046822063322249225 |
|  1 | Z     |     8 | 3.51188458428424628280046822063322249225 |
|  1 | score |     5 |                                        2 |
|  1 | score |     7 |                                        2 |
|  1 | score |     9 |                                        2 |
+----+-------+-------+------------------------------------------+

Oracle在结果行上添加组功能

1 个答案: