Python - 简单复制.csv文件出错

Question

我只使用shutil.copyfile将.csv从网络路径复制到本地路径：

from shutil import copyfile
import os.path
import _datetime as dt

fileCsv = "VDOCUMENT.csv"

srcPath = r"\\reports\"
dstPath = r"C:\Audit1\"

copyfile(os.path.join(srcPath, fileCsv), os.path.join(dstPath, fileCsv))

错误：

Traceback (most recent call last):
File "C:/Users/cvmsouz/Desktop/test/00_MoveCSV.py", line 16, in <module>
copyfile(os.path.join(srcPath, fileCsv), os.path.join(dstPath, fileCsv))
File "C:\Users\cvmsouz\AppData\Local\Continuum\Anaconda3\lib\shutil.py", line 120, in copyfile
with open(src, 'rb') as fsrc:
FileNotFoundError: [Errno 2] No such file or directory: '\\\\reports\\VDOCUMENT.csv'

Answer 1

问题实际上是愚蠢的：网络文件的名称与本地文件不同。

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