Question

我有这样的数据：

# Data
varx1 <- data.frame(datex = c("2018/01/01","2018/01/02","2018/01/03"), x = c(101,102,103)) 
varx2 <- data.frame(datex = c("2018/01/01","2018/01/02","2018/01/03","2018/01/04","2018/01/05"), x = c(10,11,12,13,14))
varx3 <- data.frame(datex = c("2018/01/01"), x = c(1000))
combination <- list(`code status OK01` = varx1, `code trx OCS02` = varx2, `Revenue 101` = varx3)
combination

我希望得到如下结果：

# Result
result <- data.frame(datex = c("2018/01/01","2018/01/02","2018/01/03","2018/01/01","2018/01/02","2018/01/03","2018/01/04","2018/01/05","2018/01/01"),
                 combination = c("code status OK01","code status OK01","code status OK01","code trx OCS02","code trx OCS02","code trx OCS02","code trx OCS02","code trx OCS02","Revenue 101"),
                 x = c(101,102,103,10,11,12,13,14,1000))
result

需要帮助解决此问题。感谢

Answer 1

我不知道变量varx3，但这样可行：

library(tidyverse)
result <- varx1 %>%
  mutate(combination="code status OK01") %>% 
  bind_rows(varx2 %>% 
              mutate(combination="code trx OCS02")) %>% 
  bind_rows(varx3 %>% 
              mutate(combination="Revenue 101")) %>% 
  select(datex, combination, x)
result

如果你想在列表中工作（鉴于列表是静态的）：

library(tidyverse)
result <- combination[[1]] %>% 
  mutate(combination="code status OK01") %>% 
  bind_rows(combination[[2]] %>% 
              mutate(combination="code trx OCS02")) %>% 
  bind_rows(combination[[3]] %>% 
              mutate(combination="Revenue 101")) %>% 
  select(datex, combination, x)
result

你指出，你有100多个变量。因此，如果您的combination数据框包含100个变量，每个变量位于一个大型列表中的单个数据框中，您可以使用：

library(tidyverse)
var_names <- names(combination)
df <- NULL
for (i in 1:length(var_names)) {
  df[[i]] <- combination[[i]] %>%
    mutate(combinate=var_names[[i]])
}
result <- bind_rows(df)
result

如何使用R将列表的名称插入到列中

1 个答案: