Question

如果我有一个数组：

["one", "two", "three", "thee", "four", "fowr"]

一个比较字符串匹配可能性的函数：

stringCompare('testing', 'testign')输出0.7

根据stringCompare()函数的结果过滤数组的最佳方法是什么 - 比如删除任何得分为0.8或以上的值，以便生成的数组为：

["one", "two", "three", "four"]

Answer 1

您也可以使用lodash：

轻松完成此操作

const array = ['one', 'two', 'two', 'three', 'four', 'three', 'two'];

const isSimilar = (s1, s2) => s1 == s2; // Switch this for your stringCompare function

const result = _.uniqWith(array, isSimilar);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.5/lodash.min.js"></script>

Answer 2

将reduce，forEach与stringCompare功能组合使用（评论内联）

＆＃13;

var stringCompare = (str1, str2) => Number(str1 == str2); //assume for the purpose of this function

//fn to get duplicate values of a particular value in an array
var getDups = (s, i, arr) => arr.slice(i + 1).filter((it, ind) => stringCompare(s, it) > 0.8);
//fn to remove duplicate values from array
var removeDups = (arr, dupArr) => dupArr.forEach(s => arr.splice(arr.indexOf(s), 1));
var arr = ["one", "two", "three", "three", "four", "four"];

var output = arr.reduce( (acc, c, i, arr) => 
     (removeDups(acc, getDups(c, i, arr)), acc), //remove duplicates from accumulator
     arr);//initialize with input arr

console.log(output);

＆＃13;

Answer 3

您可以使用filter()方法，在内部，您可以使用every()方法中的部分先前元素，并使用<= 08方法检查每个元素是否与过滤器循环中的当前元素类似const arr = ["one", "two", "three", "thee", "four", "fowr"] function compare(a, b) { let found = 0; a.split('').forEach(e => b.includes(e) && found++); return found / a.length <= 0.8; } const result = arr.filter(function(a, i) { const prev = arr.slice(0, i); return prev.every(b => compare(a, b)) }) console.log(result)。 / p>

＆＃13;

       time            id     el    conn   column1  column2  column3
2018-02-11 14:00:00     1     a      12      8        5         NaN
2018-02-11 14:00:00     1     a      12      1        NaN       NaN
2018-02-11 14:00:00     1     a      12      3        7         NaN
2018-02-11 14:00:00     1     a      12      4        12        NaN
2018-02-11 14:00:00     2     a      5       NaN      5         5
2018-02-11 14:00:00     2     a      5       NaN      3         2
2018-02-11 14:00:00     2     a      5       NaN      NaN       6
2018-02-11 14:00:00     2     a      5       NaN      7         NaN

＆＃13;

从字符串数组中过滤类似的值

3 个答案: