Question

如何使用Javascript区分相同的对象数据值？ [ES15 / ES16]

给定数据值

google.maps.event.addListener( marker, 'dragend', function ( event ) {
    document.getElementById( "input_latitude" ).value = event.latLng.lat();
    document.getElementById( "input_longitude" ).value = event.latLng.lng();
} );

之后它将会分开

[{Zone: "2"},
{Zone: "4"},
{Zone: "4"},
{Zone: "6"},
{Zone: "1"},
{Zone: "2"},
{Zone: "3"},
{Zone: "3"},
{Zone: "4"},
{Zone: "4"}]

Answer 1

一种可能的方法：

＆＃13;

var arr = [{Zone: "2"}, {Zone: "4"}, {Zone: "4"}, {Zone: "6"}, {Zone: "1"}, {Zone: "2"}, {Zone: "3"}, {Zone: "3"}, {Zone: "4"}, {Zone: "4"}]

var resp = [...new Set(arr.map(({ Zone }) => Zone))].sort().map(x => ({Zone: x}));
console.log(resp);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

对于这种新方法，您可以map上面的resp使用原始数组中filter的{{1}}作为：

＆＃13;

Zones

＆＃13;

var arr = [{Zone: "2" , Assign: "1"}, {Zone: "4", Assign: "2"}, {Zone: "4", Assign: "3"}, {Zone: "6", Assign: "4"}, {Zone: "1", Assign: "5"}, {Zone: "2", Assign: "6"}, {Zone: "3", Assign: "7"}, {Zone: "3", Assign: "8"}, {Zone: "4", Assign: "9"}, {Zone: "4", Assign: "10"}]

var resp = [...new Set(arr.map(({ Zone }) => Zone))].sort().map(x => ({Zone: x}));

var newresp = resp.map(({ Zone }) => {
  var assigns = arr.filter(x => x.Zone == Zone).map(x => x.Assign);
  return {
    Zone: Zone,
    Assign: assigns
  }
})
console.log(newresp)

＆＃13;

Answer 2

<dependency>
    <groupId>org.apache.hadoop</groupId>
    <artifactId>hadoop-mapreduce-client-core</artifactId>
    <version>2.6.0</version>
</dependency>
<dependency>
    <groupId>org.apache.hadoop</groupId>
    <artifactId>hadoop-common</artifactId>
    <version>2.6.0</version>
</dependency>
<dependency>
    <groupId>org.apache.hadoop</groupId>
    <artifactId>hadoop-mapreduce-client-jobclient</artifactId>
    <version>2.6.0</version>
</dependency>

Javascript中的不同对象值

2 个答案: