Question

我输入此代码。

<!DOCTYPE HTML>
<html>
<head>
</head>
<body>
    <div id="wrapper">
        <div id="left">
            <h1>Lorem ipsum</h1>
            <h2>Lorem ipsum</h2>
            <div id="leftbottom"></div>
        </div>
        <div id="right">
            <h1>Content ipsum</h1>
            <h2>Lorem ipsum</h2>
            <h2>Lorem ipsum</h2>
            <h2>White space</h2>
        </div>
    </div>
</body>
</html>

但是，结果在上面。

<%
    int a = 5, b = 10;
    boolean what; 
    boolean c = true, d = false;

    out.print("a :" + a + " b :" + b + "<P>");
    out.print("a<b :" + (a > b) + "<P>");

    out.print("a<=b :" + (a <= b) + "<P>");
    out.print("a==b :" + (a == b) + "<P>");
    out.print("a>b :" + (a > b) + "<P>");
    out.print("a>=b :" + (a >= b) + "<P>");
    out.print("c :" + c + "d :" + d + "<P>");
    out.print("c&&d :" + (c && d) + "<P>");
    out.print("c||d :" + (c || d) + "<P>");
    what = a > b ? true : false;
    out.print("a>b? " + what + ", !(a>b)=" + !what);
%>

a :5 b :10 aa<=b :true a==b :false a>b :false a>=b :false c :trued :false c&&d :false c||d :true a>b? false, !(a>b)=true代码在哪里？我没有输入(a<b)。但是，句子是大胆的。

Answer 1

您可能希望使用<代替<和>代替>。

a<b应为a<b

您已获得大胆，因为html被解释为代表<b>的{{1}}代码。

为什么我会收到错误（？）？

1 个答案: