Question

例如，如果我愿意：

dict(zip(states,abbreviations))

在回调中，它将返回var request = require('request'); function callback(error, response, body) { if (num) { console.log(num); } console.log(body); } var cookie = { '74358942795': 'abd7fce573c2-18c2c0de-037f-4aef-9235', '58942743795': 'e3101e9a0e28-b596998e-e879-4003-a724' } function options(num) { return { url: 'http://.../.../', method: 'POST', headers: { ... 'Cookie': cookie[num] }, body: '...=' + Date.now() }; } (function(num){ request(options(num), callback); })('74358942795');并抛出错误。

Answer 1

num不适用于callback范围。我看到的最简单的解决方案是用以下代码替换最后一个块：

(function(num){
  request(options(num), function (error, response, body){
    if (num) {
      console.log(num);
    }
    console.log(body);
  });
})('74358942795');

Answer 2

我不明白“forloop”与相关代码有什么关系。使用bind：

function callback(num, error, response, body) {
  if (num) {
    console.log(num);
  }
  console.log(body);
}

(function(num){
  request(options(num), callback.bind(null, num));
})('74358942795');

function callback(num, error, response, body) {
  if (num) {
    console.log(num);
  }
}

(function(num) {
  setTimeout(callback.bind(null, num), 1000);
})('74358942795');

Answer 3

伊戈尔的回答几乎是正确的。它应该是：

function callback(error, response, body) {
  var that = this;
  if (that.num) {
    console.log(that.num);
  }
  console.log(body);
}

(function(num){
  request(options(num), callback.bind({num}));
})('74358942795');

如何在不使用forloop的情况下传递变量来请求回调？

3 个答案: