Question

我有一个代码用于在Python中列出列表中的每个数字，但我遇到了问题。我的代码没有给我正确的答案。如果我有[2,3,4,5,6,7]，答案应为[4, 9, 16, 25, 36, 49]，但我会[49]。这是我的代码：

numList = [2,3,4,5,6,7]
def square (N):
    sq = N * N
    return (sq)
def cmput_square(numList):
    i = 0
    L = []
    while i < len (numList):
        L = [square(numList[i])]
        i = i + 1
    return (L)
n = cmput_square (numList)
print ("The squares of your numbers are:", n)

Answer 1

您的问题是，您每次都要替换L，而不是追加到L。以下应该有效：

numList = [2,3,4,5,6,7]
def square (N):
    sq = N * N
    return (sq)


def cmput_square(numList):
    i = 0
    L = []
    while i < len (numList):
        L.append(square(numList[i]))
        i = i + 1
    return (L)

n = cmput_square (numList)
print ("The squares of your numbers are:", n)

打印：

The squares of your numbers are: [4, 9, 16, 25, 36, 49]

如果您想减少所需的代码行数，可以使用列表迭代将其更改为单个函数：

def cmput_square(numList):
    return([i*i for i in numList])

[编辑] 根据您的评论，您无法使用.append或列表理解，这是另一种方式，同样作为单一功能。我认为它不那么优雅，但它可以满足你的需求：

def cmput_square(numList):
    L = [0] * len(numList)
    for i in range(len(numList)):
        L[i] = numList[i]*numList[i]
    return(L)

[编辑＃2] 并且不使用for或range，您可以这样做：

def cmput_square(numList):
    L = [0] * len(numList)
    i = 0
    while i < len(numList):
        L[i] = numList[i]*numList[i]
        i = i+1
    return(L)

Answer 2

您创建列表的当前方式会在每次调用时用一个项目列表覆盖L.你可以使用L.append(square(numList[i]))代替L = [square(numList[i])]，你可以通过列表理解在一行中创建整个列表：

def cmput_square(numList):
    return [square(i) for i in numlist]

Answer 3

生日快乐 - 只需使用.append（）

numList = [2,3,4,5,6,7]
def square (N):
    sq = N * N
    return (sq)
def cmput_square(numList):
    i = 0
    L = []
    while i < len (numList):
        L.append(square(numList[i]))
        i += 1
    return (L)
n = cmput_square (numList)
print ("The squares of your numbers are:", n)

Answer 4

替换

L = [square(numList[i])]

与

L += [square(numList[i])]

如果您想要更短的版本：

numList = [2,3,4,5,6,7]
L = [numList[i]**2 for i in range(len(numList))]
print ("The squares of your numbers are:", L)

需要帮助编辑在列表中排列数字的Python代码吗？

4 个答案: