如何根据存储在数组中的复选框值输出响应?

时间:2018-03-11 20:58:44

标签: javascript html local-storage

我有持久的复选框,代表一周的日子。我能够将这些值存储在数组localStorage中,以便它们在刷新后保留。

我想知道的是如何根据天数的选择输出“工作日”或“周末”?例如,用户选择“星期一”和“星期三”,输出是“工作日”

我已经使用案例对其进行了测试,但未能成功应用localStorage的值。如何将我的值存储在数组中有什么问题吗?

Here is my codepen

我存储和保持值的功能:

function updateStorage() {
    $checkboxes.each(function() {
        formValues[this.id] = this.checked;
    });

    localStorage.setItem("formValues", JSON.stringify(formValues));
}

$checkboxes.on("change", function() {
    updateStorage();
});

// On page load
$.each(formValues, function(key, value) {
    $("#" + key).prop('checked', value);
});

3 个答案:

答案 0 :(得分:0)

这是问题所在。一旦写入Localstorage,您需要删除该项目才能重新编写它

//checkbox

//function for persistent checkbox     
var formValues = JSON.parse(localStorage.getItem('formValues')) || {};
var $checkboxes = $("#checkbox-wrapper :checkbox");

function updateStorage(){
  $checkboxes.each(function() {
    formValues[this.id] = this.checked;
  });
  localStorage.removeItem('formValues');
  localStorage.setItem("formValues", JSON.stringify(formValues));
}

$checkboxes.on("change", function(){
  updateStorage();
});

// On page load

$.each(formValues, function(key, value) {
  $("#output").html($("#output").html() + key + ": " + value + "<br/>")
});

我使用上面的代码更新了你的代码并且它可以正常工作。

答案 1 :(得分:0)

这是一个函数,它将检查你的days对象并返回一个具有2个布尔属性(isWeekDayisWeekendDay)的对象:

function checkweekday(days) {
  console.log('days', days);
  var weekDays = ['monday', 'tuesday', 'wednesday', 'thursday', 'friday'];
  var weekendDays = ['saturday', 'sunday'];
  var isWeekDay = false;
  var isWeekendDay = false;
  for (var day in days) {
    if (days[day]) {
      if (day) {
        if (weekDays.indexOf(day) > -1) {
          isWeekDay = true;
        }
        if (weekendDays.indexOf(day) > -1) {
          isWeekendDay = true;
        }
      }
    }
  }
  return {
    isWeekDay: isWeekDay,
    isWeekendDay: isWeekendDay
  }
}

从localStorage检索值后,使用该对象调用该函数。

var formValues = JSON.parse(localStorage.getItem('formValues')) || {};
var check = checkweekday(formValues);
console.log(check);

这是updated plunkr

答案 2 :(得分:0)

我希望你的意思是这样的

//checkbox

//function for persistent checkbox     
var formValues = JSON.parse(localStorage.getItem('formValues')) || {};
var $checkboxes = $("#checkbox-wrapper :checkbox");

function outputResult(isWeekday,isWeekend){

  var output = ""
  if( isWeekday && isWeekend ) output = "Both";
  else if( isWeekday ) output = "Weekday";
  else if( isWeekend ) output = "Weekend";
  document.getElementById("output").innerHTML = output;

}

function checkDay(){

    var isWeekday = false;
    var isWeekend = false;

    $checkboxes.each(function(){
      if( this.checked ){
        if( this.id == "saturday" || this.id == "sunday" ) isWeekend  = true;
        else isWeekday = true;
      }
    });

  outputResult(isWeekday,isWeekend);
}

function updateStorage(){

  $checkboxes.each(function(){
    formValues[this.id] = this.checked;
  });

  localStorage.setItem("formValues", JSON.stringify(formValues));

  checkDay();
}

$checkboxes.on("change", function(){
  updateStorage();
});

// On page load
$.each(formValues, function(key, value) {
  $("#" + key).prop('checked', value);
});

https://codepen.io/anon/pen/gepomY?editors=1011