Question

以下是我所拥有的一系列句子

$strings = [ 
  "I want to match docs with a word New", 
  "But I don't want to match docs with a phrase New York", 
  "However I still want to match docs with a word New which has a phrase New York", 
  "For example let's say there's a New restaraunt in New York and I want this doc to be matched."
]

我希望将上面的句子与 new 字符串相匹配。但是，当 new 后跟 york 时，我不希望与句子匹配。我希望能够匹配在某个小字距离A内没有预先/后跟字B的任何字N。不在'A＆＃39;旁边。

如何使用正则表达式实现预期结果？

Answer 1

具有负向前瞻的正则表达式应该可以解决问题（访问this link进行工作演示）：

.*[Nn]ew(?! [Yy]ork).*

从PHP实施的角度来看，您可以使用preg_match function，如下所示：

$strings = [ 
    "I want to match docs with a word New", 
    "But I don't want to match docs with a phrase New York", 
    "However I still want to match docs with a word New which has a phrase New York", 
    "For example let's say there's a New restaraunt in New York and I want this doc to be matched."
];

foreach ($strings as $string) {
    echo preg_match('/.*new(?! york).*/i', $string)."\n";
}

输出结果为：

1 -> Match
0 -> Discarded
1 -> Match
1 -> Match

Answer 2

这应该有效：

/(new[^ ?york])|(a[^b])/gi

DEMO

PHP正则表达式在任何时候与单词匹配时，如果它不是后跟另一个单词

2 个答案: